A rectangular open channel, with a constant discharge of 32m3/s32, has a smooth expansion from (1) to (2) as shown in figure Q2 in the flow direction. At (1) the channel is 3.6m wide and the water depth is 2.4m. At (2) the water depth is 0.8m. After the expansion, the channel width remains constant. Explain what engineering techniques you could use in order for the flow to change regime at a point downstream of (2).

Q: A rectangular open channel, with a constant discharge of 32m3/s, has a smooth expansion from (1) to…

A: open channel flow : A sort of liquid flow within a conduit or in a channel with a free surface,…

Q: A downward step of height 0.5 m causes a hydraulic jump in a wide channel when the depth and…

A: Given :

Q: 1- A uniform flow passes through a rectangular channel having a width of 4 m. The channel carriers a…

A: Note: Since you have posted a question with multiple sub parts, we will provide the solution only to…

Q: Q1) In a rectangular channel with a base width of 3 m, the depth of the water is 0.5 m and the flow…

A: The channel is rectangularWidth of base, B = 3 mDepth of water, y1 = 0.5 mVelocity of flow, V1 = 5…

Q: A 3 m wide rectangular channel, as shown, carries a flow of 11.7m³/s. hydraulic jump Ус y2 2 Az =…

A: Given data: rectangular channel width = 3 m Discharge = 11.7 m3/s At section 3 hump = 0.4 m

Q: In a 5 m wide rectangular channel, the velocity u distribution in the vertical direction y is given…

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Q: A trapezoidal channel is to be designed for the maximum efficiency to carry a discharge of 10m2/s.…

A: The maximum efficiency of the channel is achieved by calculating the dimension for the hydraulically…

Q: Consider a 20-ft wide rectangular channel with a Manning's n value of 0.03. The channel has a…

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Q: A trapezoidal channel has a bottom width of 6 m and side slope of 1:1. The depth of flow is 2 m at a…

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Q: A trapezoidal channel has a bottom width of 6m and side slope of 1:1. The depth of flow is 2m at a…

A: Bottom width = 6 mside slope = 1:1Depth of flow = 2 mDischarge = 24 m3/secTo find :Specific energy ?

Q: Y1 V2

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Q: Calculate the normal discharge for a depth of 1.5 m in m³/s, to the nearest 100th.

A: Given:- Normal depth, y = 1.5 m Slope = 0.27 m per 100 m

Q: Water flows over the spillway shown in the figure below. If the velocity is uniform at sections (1)…

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Q: b. Figure 3.2 is the flow of a channel having a large width, b, under a sluice gate. Assuming…

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Q: 9. Open channel flow is: a) Liquid surface is subject to Hydraulic pressure b) Liquid surface is…

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Q: Q3. Water flows down a dam spillway and then forms a hydraulic jump. Just before the jump, the…

A: Given data: Before jump depth of flow (y1) = 0.15m Velocity of flow (V1) = 7.5m/s After jump depth…

Q: Consider a rectangular channel of width b=7.5 m, in which the hydraulic jump occurs and one of its…

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Open Channel Flow

Open channel flow is a branch of fluid mechanics. It deals with the flow of fluid in an open conduit or free surface. In an open channel flow, gravity induces the flow of water whose surface is open to the air. This flow is free-falling rather than confined in rigid body conduits. The open channel flow depends upon two parameters that are the cross-section of the conduit and the velocity profile. Practical examples of open channel flow are streams, rivers, canals, and other drainage systems.In open channel flow, the cross-sectional area of at least one of the sides is exposed to air, and the surface of water faces atmospheric pressure. This flow is also known as free gravity flow. The cross-sectional area of the conduit can be either man-made or a natural channel. For instance, the flow in rivers and streams are natural conduits, and the flow in a canal and sanitary systems are man-made or engineered channels.