Example 14.5 Consider H,: H1 = Hz = H3= H4= H5 (a) Complete the following ANOVA table. Mean Squares Sum of Squares SS Degrees of Freedom df Source of Variation F MS 132 Between samples Within samples Total 532 44 (b) Test the hypothesis at (i) 5 percent level of significance (ii) 1 percent level of significance and interpret the results.
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- Mar 27 38% AA Amylab.pearson.com J C + O arnament 406... OneLogin DAL MyLab and Mastering... P Quiz 10 (7.1) MW Cristina Ramos This quiz: 2 point(s) possible Quiz 10 (7.1) This question: 1 Submit quiz point(s) possible 1 list K Find the sample size needed to estimate the percentage of adults who can wiggle their ears. Use a margin of error of 4 percentage points and use a confidence level of 95%. Complete parts (a) and (b) below. a. Assume that p and q are unknown. 2 n = (Round up to the nearest integer.) b. Assume that 25% of adults can wiggle their ears. n = ☐ (Round up to the nearest integer.)Data in the following Table 6 represent the number of hours of relief provided by five different brandsof headache tablets given to 25 patients experiencing fevers of 38° Celsius or more. Perform theanalysis of variance (ANOVA) and test the hypothesis at 0.05 level of significance that the mean numberof hours of relief provided by the tablets is the same for all five brands. Provide your evidence.Table 6 tablet brand A B C numbers of hours of relief 5.2 9.1 2.4 numbers of hours of relief 4.7 7.1 3.4 numbers of hours of relief 8.1 8.2 4.1 numbers of hours of relief 6.2 6.0 1.0 numbers of hours of relief 3.0 9.1 1.0Take the variable Car as a random block. Do different additives have significantly different effect on boosting gas mileage? Groups Name Variance Std.Dev. car:additive (Intercept) 0.9865 0.9932 car (Intercept) 2.3299 1.5264 Residual 0.6707 0.8190 Number of obs: 36, groups: car:additive, 9; car, 3 Analysis of Variance Table npar Sum Sq Mean Sq F value additive 2 4.5419 2.271 3.3857
- Data is collected to compare two different types of batteries. We measure the time to failure of 10 batteries of each type. Battery A: mean= 8.65 Battery B: mean=11.23 Assume equal variances. Perform a .05 level test to determine if Battery B outlasts Battery A by more than 2 hours. Use Sp= .88569 What is the Chart Value for this problem?In the attached picture, the data for the perceived level of stress of 30 employees is recorded. Also, researchers exposed the employees to either early or late stressors before completing the stress questionnaire. Attached is also the output for the data after conducting a two way ANOVA Discuss the two kinds of variance here, and indicate how they are compared to conclude a significant difference.The accompanying table lists pulse rates. Use a 0.05 significance level and apply the methods of two-way analysis of variance. What is the conclusion? Click on the icon to view the data table. State the null and alternative hypotheses in the test for the effect of an interaction between row and column factors. Ho: There interaction between gender and age. H₁: There interaction between gender and age. Pulse Rates for Gender and Age C Under 30 Years of Age Over 30 Years of Age Female 78 103 78 63 61 98 81 98 91 95 77 75 73 65 71 78 61 71 74 55 Female Male 60 81 56 69 68 74 75 68 63 56 46 70 61 65 91 80 59 58 64 59 Male Print Done D
- An experiment to explore the pain threshold to electrical shocks for males and females resulted in the data summary given below. Do the data provide sufficient evidence to indicate s significant difference in the variability of pain threshold for men and women. Use a = .10. What can be said about p-value? Sample Size Mean Variance Males 14 16.2 2.7 Females 10 14.9 26.4Two small separate between-subjects design experiments were performed and their means are given in the tables below. Note that by coincidence these are identical between experiments. However, when statistical tests were performed (single factor between- subjects ANOVA) it was found that one pair of differences was significant but not the other. Mean Experiment 1 Level A1 Level A2 20 15 Significance (ANOVA) p> .05 NS Mean Experiment 2 Level A1 Level A2 20 15 Significance (ANOVA) p<.05 sig Briefly suggest and comment upon the possible reasons why, for a between- subjects design, identical pairs of means can have a significant difference in one instance, but a non-significant difference in another. Relate these suggestions to the two experiments shown here. Assume that the statistical tests were performed correctly.Interpret these results of a Two-Way Anova Analysis with the given info.
- A recent Nielsen analysis found that the typical U.S. smartphone user is spending an average of 220 minutes per day using apps. We speculate that the average time spent using apps for Generation X smartphone users (aged 41-56 years) is less than the national average. The hypotheses are Ho: H = 220 minutes versus Ha: µ < 220 minutes. Summary results from R are provided. Summary Statistics Std. Dev (s) Mean Sample Size (n) 205 minutes 63.25 minutes 31A random sample of 40 companies with assets over $10 million was surveyed and asked to indicate their industry and annual computer technology expense. The ANOVA comparing the average computer technology expense among three industries rejected the null hypothesis. The mean square error (MSE) was 195. The following table summarized the results: Education Tax Services Food Services Number Sampled 10 14 16 Mean Expense (1,000,000s) 2 15.5 20 When comparing the mean annual computer technology expense for companies in the tax services and education industries, which of the following 95% confidence interval can be constructed?A bank wants to determine whether a customer's current balance can be used to predict future earning potential. What would be the most appropriate procedure to use to analyze data to answer this question? Only choose a test that handles multiple comparisons if such a test is needed. O Chi-square test of association O ANOVA (Analysis of Variance) O Regression Test of Slope or Correlation O Test for a Difference of Proportions O Test for a Difference of Means