I test the effect of temperature of a manufacturingprocess on the lifetime of its product, I collected data shownbelow.Factor: temperatureLevel(degrees)100LifetimeSumAverageVariance11550110, 120110, 130120, 120110, 120230200240120200300240120115117,540023050Total Averagea. Write the hypotheses of this ANOVA test.b. Calculate the sum of squares for the ANOVA table.c. Make the ANOVA table.squares above, use 100, 200, and 300 for the values in thetable below.)(If you could not find the sumof -d. With a- 10%, make a decision.

Given: 100 degree 110 120 200 degree 110 130 300 degree 120 120 400 degree 110 120

Answered: I test the effect of temperature of a…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Mean 1001 206 Levene's Test for Equality of Variances Sig. 15.578 <.001 .510 1.402 df Sig. (2-tailed) 1205 .014 261.832 035 -3.168 -3.168 Std. Error Difference 3. Do Whites spend a significantly different amount of time on the internet (WWWHR) than Blacks? Group Statistics Std. Error Race of respondent N Std. Deviation Mean Www.hours per week WHITE 13.29) (16.124) BLACK 16.46 20.120 Independent Samples Test t-test for Equality of Means Mean t Difference Www hours per week -2.455 Equal variances assumed -2.124 Equal variances not assumed 1.291 1.492 95% Confidence Interval of the Difference Lower Upper -5.701 -6.106 -.636 -.231
Statistics students in Oxnard College sampled 11 textbooks in the Condor bookstore and recorded the number of pages in each textbook and its cost. The bivariate data are shown below: Number of Pages (xx) Cost(yy) 827 126.78 864 135.96 492 93.88 436 72.04 622 94.08 694 112.16 747 114.58 806 131.84 952 152.28 733 118.62 384 59.76 A student calculates a linear modelyy = ______x +________ . (Please show your answers to two decimal places)Use the model to estimate the cost when number of pages is 638.Cost = $ _____________(Please show your answer to 2 decimal places.)
A one-way Analysis of Variance (ANOVA) was used to examine whether students’ scores on a standardized test is a function of the teaching method they received (either lecture only, hands-on learning only, or both together). The ANOVA was significant. Run post hoc tests (by hand!) to determine which pairs of the mean are significantly different. Do the math for each and then explain in what way are they different. Method N Mean SD Source df SS MS F Lecture Only 15 82.8 9.59 Between 2 736.53 368.27 5.34 Hands-On Only 15 88.53 8.73 Within 42 2895.47 68.94 Both 15 92.67 6.22 Total 44 3632 Total 45 88
Assume the samples are random and independent, the populations are nomally distributed, and the population variances are equal. The table available below shows the prices (in dollars) for a sample of automobile batteries. The prices are classified according to battery type. At a = 0.10, is there enough evidence conclude that at least one mean battery price is different from the others? Complete parts (a) through (e) below. E Click the icon to view the battery cost data. (a) Let u1. P2. H3 represent the mean prices for the group size 35, 65, and 24/24F respectively. Identify the claim and state Ho and H. H Cost of batteries by type The claim is the V hypothesis. Group size 35 Group size 65 Group size 24/24F 101 111 121 124 D 146 173 182 278 124 140 141 89 (b) Find the critical value, Fo, and identify the rejection region. 90 79 84 The rejection region is F Fo, where Fo = (Round to two decimal places as needed.) (c) Find the test statistic F. Print Done F= (Round to two decimal places as…
You are testing the claim that the mean GPA of night students is different from the mean GPA of day students. A sample of 24 night students and 28 day students and their GPA's are recorded below. Test the claim using a 1% level of significance. Assume the population variances are unequal and that GPAs are normally distributed. Give answers to 4 decimal places. GPA-Night GPA-Day 3.05 3.38 2.91 3.02 3.27 3.4 3.29 2.73 3.3 3.24 3.35 2.69 3.39 3.25 3.52 3.33 3.39 2.33 3.25 3.51 3.08 3.07 3.27 2.9 3.32 3.48 3 2.94 3.62 2.93 3.64 3.31 3.54 2.62 3.45 2.66 3.29 3.27 3.56 2.76 3.15 2.7 3.4 3.27 3.51 2.96 3.54 2.86 3.24 2.72 2.64 3.14 What are the correct hypotheses? Note this may view better in full screen mode. Select the correct symbols in the order they appear in the problem.H0: Select an answer x̅₂ s² x̅₁ σ² μ₂ μ₁ p ? = ≠ > < ≥ ≤ Select an answer 0 μ₂ x̅₂ x̅₁ σ² p s² μ₁ H1: Select an answer σ² x̅₂ x̅₁ μ₁ μ₂…
When you are conducting an ANOVA, the total variance in the dependent variable is divided into variance that is due to differences between individuals _______ groups and variance due to differences _______ groups. Group of answer choices above; within over; between above; between within; between
You are testing the claim that having lights on at night increases weight gain (abstract). A sample of 10 mice lived in an environment with bright light on all of the time and 8 mice who lived in an environment with a normal light/dark cycle is given below. Test the claim using a 10% level of significance. Assume the population variances are unequal and that the weight changes are normally distributed. Give answers to 3 decimal places. Data available at StatKey, choose Mice Wgt Gain-2e data set Light (x₁) 1.71 4.67 4.99 5.33 5.43 6.94 7.15 9.17 10.26 11.67 What are the correct hypotheses? Note this may view better in full screen mode. Select the correct symbols in the order they appear in the problem. Ho: Select an answer ? V Select an answer V Ha: Select an answer ✓ Based on the hypotheses, find the following: Test Statistic = Dark (₂) 2.27 2.53 2.83 4 4.21 4.6 5.95 6.52 p-value = ? V Select an answer V (Hint: difference in means from Ha) The correct decision is to Select an answer…
You are testing the claim that having lights on at night increases weight gain (abstract). A sample of 10 mice lived in an environment with bright light on all of the time and 8 mice who lived in an environment with a normal light/dark cycle is given below. Test the claim using a 6% level of significance. Assume the population variances are unequal and that the weight changes are normally distributed. Give answers to 3 decimal places. Data available at StatKey, choose Mice Wgt Gain-2e data set Light (x1x1) Dark (x2x2) 1.71 2.27 4.67 2.53 4.99 2.83 5.33 4 5.43 4.21 6.94 4.6 7.15 5.95 9.17 6.52 10.26 11.67 H0: μ₁ = μ₂Ha: μ₁ > μ₂ Based on the hypotheses, find the following:Test Statistic = __________ (Hint: difference in means from Ha)p-value = ___________________
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We give the total variation, the unexplained variation (SSE), and the least squares point estimate b1 . Total variation = 13.459; SSE = 2.806; b1 = 2.6652 Click here for the Excel Data File Using the information given, find the explained variation, the simple coefficient of determination (r2), and the simple correlation coefficient (r). Interpret r2. (Round your answers to 3 decimal places. Round your percent to 1 decimal place.) Explained variation r2 r % of the variation in demand can be explained by variation in price differential.
Statistics students believe that the mean score on a first statistics test is 65. The instructor thinks that the mean score is higher. She samples 10 statistics students and obtains the scores: Grades 73.5 88 63.9 85.5 62.7 65 83.2 61.9 88 62.7 Test grades are believed to be normally distributed.Use a significance level of 5%. State the alternative hypothesis: HA:HA: μ>65μ>65 μ<65μ<65 μ≠65μ≠65 State the mean of the sample: State the standard error of the sample means: State the test statistic: t=t= State the p-value: Decision: Fail to reject the null hypothesis. Reject the null hypothesis.

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