Example 11.1: A solution of sodium nitrate in water contains 48 % NaNO3 by weight at 313 K (40° C) temperature. Calculate the percentage yield of NaNO3 crystals that may be obtained when the temperature is reduced to 283 K (10° C). Also, calculate the quantity of NaNO3 crystals obtained from 100 kg of the solution. Data: Solubility of NaNO3 in water at 283 K (10° C) is 80.18 kg NaNO3 per 100 kg water.

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
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Calculate the quantity of NaNO3 crystals obtained from 100kg of the solution.

Example 11.1: A solution of sodium nitrate in water contains 48 % NaNO3 by weight at
313 K (40° C) temperature. Calculate the percentage yield of NaNO3 crystals that may be
obtained when the temperature is reduced to 283 K (10° C). Also, calculate the quantity of
NaNO3 crystals obtained from 100 kg of the solution.
Data: Solubility of NaNO3 in water at 283 K (10° C) is 80.18 kg NaNO3 per 100 kg
water.
Transcribed Image Text:Example 11.1: A solution of sodium nitrate in water contains 48 % NaNO3 by weight at 313 K (40° C) temperature. Calculate the percentage yield of NaNO3 crystals that may be obtained when the temperature is reduced to 283 K (10° C). Also, calculate the quantity of NaNO3 crystals obtained from 100 kg of the solution. Data: Solubility of NaNO3 in water at 283 K (10° C) is 80.18 kg NaNO3 per 100 kg water.
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