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Ambient temperature water (~ 20 °C) flows through a horizontal, 100 m long, square channel that has the same cross-sectional area as a 5" schedule 40 pipe and the same surface roughness as cast iron. a) Calculate the hydraulic diameter for the square channel. L=100m P= = 998 kg/m³ = 1,01x (0-3 N.s/m² M e = 0.26 mm = 0.00026 m D₁ = 4A ANS: () Dn= 0.1136m

Ambient temperature water (~ 20 °C) flows through a horizontal, 100 m long, square channel that has the same cross-sectional area as a 5" schedule 40 pipe and the same surface roughness as cast iron. a) Calculate the hydraulic diameter for the square channel. L=100m P= = 998 kg/m³ = 1,01x (0-3 N.s/m² M e = 0.26 mm = 0.00026 m D₁ = 4A ANS: () Dn= 0.1136m

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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QUESTION 3 Ambient temperature water (~ 20 °C) flows through a horizontal, 100 m long, square channel that has the same cross-sectional area as a 5" schedule 40 pipe and the same surface roughness as cast iron. a) Calculate the hydraulic diameter for the square L=100 m p=998 kg/m³ 1,01x (0-3 N.s/m² M = e = 0.26 mm = 0.00026m channel. D₁ = 4A ANS D₁ = 0.1136m :
Transcribed Image Text:QUESTION 3 Ambient temperature water (~ 20 °C) flows through a horizontal, 100 m long, square channel that has the same cross-sectional area as a 5" schedule 40 pipe and the same surface roughness as cast iron. a) Calculate the hydraulic diameter for the square L=100 m p=998 kg/m³ 1,01x (0-3 N.s/m² M = e = 0.26 mm = 0.00026m channel. D₁ = 4A ANS D₁ = 0.1136m :
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