**Transcription and Analysis of Reaction Using Standard State Free Energies****Reaction Analysis:**The image presents a biochemical reaction involving ATP hydrolysis to ADP and the transfer of a phosphate group. The structures involved include a nucleotide and a sugar phosphate compound.**Table of Standard State Free Energies:**| Compound | ΔG°' (kJ/mol) hydrolysis ||------------------------|--------------------------|| Phosphoenolpyruvate | -62 || Creatine phosphate | -43 || ATP | -32 || Glucose-1-phosphate | -21 || Glucose-6-phosphate | -14 |**Problems:****A) Calculate the standard state free energy change for the reaction (in the direction shown).**1. Identify the compounds involved from the table: - The reaction involves ATP hydrolysis to produce ADP and a phosphorylated sugar.2. Use the given ΔG°' values: - ATP hydrolysis: ΔG°' = -32 kJ/mol3. Calculate the overall standard state free energy change using the provided data.**B) Under standard state conditions, will this reaction proceed to the LEFT (down) or RIGHT (up)?**1. Determine the directionality based on the ΔG°' value calculation: - Negative ΔG°' indicates a reaction that proceeds spontaneously in the given direction (right/up). - Positive ΔG°' would indicate the reverse direction.**Graphical Explanation:**- The reaction diagram shows ATP interacting with a sugar molecule, resulting in the transfer of a phosphate group.- The diagram includes molecular structures illustrating the reactants' transformation to products upon phosphate transfer.**Conclusion:**Based on the standard free energy change from ATP hydrolysis being negative, this reaction is likely to proceed to the right under standard state conditions, releasing energy as the phosphate group is transferred. This demonstrates a typical biochemical energetics calculation used to predict reaction feasibility and direction.

In the given reaction, two processes occur: 1. Reverse of hydrolysis of phosphoenolpyruvate (because in hydrolysis, one phosphate is lost, but here one is added) 2. Hydrolysis of Glucose-1-phosphateFor hydrolysis of glucose-1-phosphate, Gibbs free energy change = -21 kJ/mol For hydrolysis of phosphoenolpyruvate, Gibbs free energy change = -62 kJ/mol, so for the reverse process, the Gibsb free energy change = +62 kJ/molSo, for the overall process, ∆G=+62-21 kJ/mol∆G=41 kJ/mol