Ex2:) If I have 4 moles of a gas at a pressure of 5.6 atm and a volume of 12 liters, what is the tem List Variables: Formula: P V =nRT P = Solve: V = n = T = K= °C + 273 = ? K Gas Constant (R) R =

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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Ex2:) IfI have 4 moles of a gas at a pressure of 5.6 atm and a volume of 12 liters, what is the temperature?
List Variables:
Formula: P V =nRT
P =
Solve:
V =
n =
T =
K= °C + 273 = ? K
Gas Constant (R)
R =
Transcribed Image Text:Ex2:) IfI have 4 moles of a gas at a pressure of 5.6 atm and a volume of 12 liters, what is the temperature? List Variables: Formula: P V =nRT P = Solve: V = n = T = K= °C + 273 = ? K Gas Constant (R) R =
Example 1: Average lung capacity for a person is 4 liters. At 37°C (body temperature)
and 110kPa, how many moles of Oxygen gas can your lungs hold?
List Variables:
Formula: P V =n R T
P = 110 kPa
Solve: (110 kPa) x (4L) = n (8.314 L kPa / mol K) x (310K)
V 4L
440 kPa L
=n (2577.34 L kPa / mol)
n = ?
440 kPa L
2577.34 L kPa mol
T= 37°C
In
K= 37 + 273 = 310 K
Gas Constant (R)
0.171 mol O,
In
R = 8.314 L kPa /
mol K
Ex2-) IfI have 4 moles of a gas at a pressur
Transcribed Image Text:Example 1: Average lung capacity for a person is 4 liters. At 37°C (body temperature) and 110kPa, how many moles of Oxygen gas can your lungs hold? List Variables: Formula: P V =n R T P = 110 kPa Solve: (110 kPa) x (4L) = n (8.314 L kPa / mol K) x (310K) V 4L 440 kPa L =n (2577.34 L kPa / mol) n = ? 440 kPa L 2577.34 L kPa mol T= 37°C In K= 37 + 273 = 310 K Gas Constant (R) 0.171 mol O, In R = 8.314 L kPa / mol K Ex2-) IfI have 4 moles of a gas at a pressur
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