Evaporating sweat cools the body because evaporation is an endothermic process: H₂O(l) → H₂O(g) A Hxn +44.01 kJ Part A Estimate the mass of water that must evaporate from the skin to cool the body by 1.20 °C. Assume a body mass of 85.0 kg and assume that the specific heat capacity of the body is 4.00 J/g.° C. Express your answer in grams to three significant figures. m = 15| ΑΣΦΑ ? g
Evaporating sweat cools the body because evaporation is an endothermic process: H₂O(l) → H₂O(g) A Hxn +44.01 kJ Part A Estimate the mass of water that must evaporate from the skin to cool the body by 1.20 °C. Assume a body mass of 85.0 kg and assume that the specific heat capacity of the body is 4.00 J/g.° C. Express your answer in grams to three significant figures. m = 15| ΑΣΦΑ ? g
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Evaporation and Cooling: An Endothermic Process**
*Explanation:*
Evaporating sweat cools the body because evaporation is an endothermic process, as represented by the chemical equation:
\[ \text{H}_2\text{O} (l) \rightarrow \text{H}_2\text{O} (g) \]
With an enthalpy change (\(\Delta H^\circ_{\text{rxn}}\)) of \(+44.01 \, \text{kJ}\).
**Activity: Estimation Problem**
*Part A*
Calculate the mass of water that must evaporate from the skin to cool the body by \(1.20 \, ^\circ \text{C}\). Assume a body mass of \(85.0 \, \text{kg}\) and a specific heat capacity of the body is \(4.00 \, \text{J/g} \cdot ^\circ \text{C}\).
*Task:* Express your answer in grams to three significant figures.
Input field provided for answer (mass, \(m\), in grams).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa684ef64-b106-44e3-b477-7930de74cd26%2Ff8f50440-60a9-47dd-8b6e-31c401a00c28%2Fkvr3cl_processed.png&w=3840&q=75)
Transcribed Image Text:**Evaporation and Cooling: An Endothermic Process**
*Explanation:*
Evaporating sweat cools the body because evaporation is an endothermic process, as represented by the chemical equation:
\[ \text{H}_2\text{O} (l) \rightarrow \text{H}_2\text{O} (g) \]
With an enthalpy change (\(\Delta H^\circ_{\text{rxn}}\)) of \(+44.01 \, \text{kJ}\).
**Activity: Estimation Problem**
*Part A*
Calculate the mass of water that must evaporate from the skin to cool the body by \(1.20 \, ^\circ \text{C}\). Assume a body mass of \(85.0 \, \text{kg}\) and a specific heat capacity of the body is \(4.00 \, \text{J/g} \cdot ^\circ \text{C}\).
*Task:* Express your answer in grams to three significant figures.
Input field provided for answer (mass, \(m\), in grams).
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