A student heats 68.15 grams of silver to 98.73 °C and then drops it into a cup containing 78.21 grams of water at 23.04 °C. She measures the final temperature to be 26.47 °C. The heat capacity of the calorimeter (sometimes referred to as the calorimeter constant) was determined in a separate experiment to be 1.88 J/ °C. Assuming that no heat is lost to the surroundings calculate the specific heat of silver. Specific Heat (Ag) = J/g°C.
A student heats 68.15 grams of silver to 98.73 °C and then drops it into a cup containing 78.21 grams of water at 23.04 °C. She measures the final temperature to be 26.47 °C. The heat capacity of the calorimeter (sometimes referred to as the calorimeter constant) was determined in a separate experiment to be 1.88 J/ °C. Assuming that no heat is lost to the surroundings calculate the specific heat of silver. Specific Heat (Ag) = J/g°C.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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![A student heats 68.15 grams of silver to 98.73 °C and then drops it into a cup containing 78.21 grams of water at 23.04 °C. She measures the
final temperature to be 26.47 °C.
The heat capacity of the calorimeter (sometimes referred to as the calorimeter constant) was determined in a separate experiment to be 1.88 J/
°C.
Assuming that no heat is lost to the surroundings calculate the specific heat of silver.
Specific Heat (Ag) =
J/g°C.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F186f09f4-984a-4a29-9587-a837fa894e4a%2F6c61cd52-da73-4ef5-849e-dfee2ff8df2d%2F3kyw04.png&w=3840&q=75)
Transcribed Image Text:A student heats 68.15 grams of silver to 98.73 °C and then drops it into a cup containing 78.21 grams of water at 23.04 °C. She measures the
final temperature to be 26.47 °C.
The heat capacity of the calorimeter (sometimes referred to as the calorimeter constant) was determined in a separate experiment to be 1.88 J/
°C.
Assuming that no heat is lost to the surroundings calculate the specific heat of silver.
Specific Heat (Ag) =
J/g°C.
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