et x be a continuous random variable that has a normal distribution with μ = 48 and robability that the sample mean, x, for a random sample of 16 taken from this populat Round your answer to four decimal places. (x > 44.90) = i

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**Problem Statement:**

Let \( x \) be a continuous random variable that has a normal distribution with \( \mu = 48 \) and \( \sigma = 8 \). Assuming \( \frac{n}{N} \leq 0.05 \), find the probability that the sample mean, \( \bar{x} \), for a random sample of 16 taken from this population will be more than 44.90.

Round your answer to four decimal places.

\[ P(\bar{x} > 44.90) = \] [Input Box]

---

**Explanation:**

1. **Parameters Given:**
   - Population Mean (\( \mu \)): 48
   - Population Standard Deviation (\( \sigma \)): 8
   - Sample Size (\( n \)): 16
   - Sample Mean (\( \bar{x} \)): 44.90
   - Finite Population Correction Factor (Assuming \( \frac{n}{N} \leq 0.05 \))

2. **Goal:**
   - To determine the probability that the sample mean \( \bar{x} \) for a random sample of 16 is greater than 44.90.

3. **Steps to Follow:**
   - Calculate the standard error of the mean (SEM), which will be \( \frac{\sigma}{\sqrt{n}} \).
   - Convert the sample mean to a z-score using \( Z = \frac{\bar{x} - \mu}{SEM} \).
   - Use the z-score to find the corresponding probability from the standard normal distribution.

4. **Notes:**
   - Round the final answer to four decimal places.
Transcribed Image Text:**Problem Statement:** Let \( x \) be a continuous random variable that has a normal distribution with \( \mu = 48 \) and \( \sigma = 8 \). Assuming \( \frac{n}{N} \leq 0.05 \), find the probability that the sample mean, \( \bar{x} \), for a random sample of 16 taken from this population will be more than 44.90. Round your answer to four decimal places. \[ P(\bar{x} > 44.90) = \] [Input Box] --- **Explanation:** 1. **Parameters Given:** - Population Mean (\( \mu \)): 48 - Population Standard Deviation (\( \sigma \)): 8 - Sample Size (\( n \)): 16 - Sample Mean (\( \bar{x} \)): 44.90 - Finite Population Correction Factor (Assuming \( \frac{n}{N} \leq 0.05 \)) 2. **Goal:** - To determine the probability that the sample mean \( \bar{x} \) for a random sample of 16 is greater than 44.90. 3. **Steps to Follow:** - Calculate the standard error of the mean (SEM), which will be \( \frac{\sigma}{\sqrt{n}} \). - Convert the sample mean to a z-score using \( Z = \frac{\bar{x} - \mu}{SEM} \). - Use the z-score to find the corresponding probability from the standard normal distribution. 4. **Notes:** - Round the final answer to four decimal places.
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