Q13. Suppose that a certain type of electronic component follows an exponential distribution with a mean life of 500 hours. Let X be the sample average of the life of 25 electronic components. (a) Find the mean and variance of X. (b) Use Chebyshev's inequality to find a lower bound for P(300 < X < 700). (c) Find P(300 < X < 700), by using the central limit theorem and the table of the standard normal cumulative distribution given on the last page.

Q: Radioactive Carbon-14 The percentage Pof radioactive carbon- 14 remaining in a fossil after t years…

A: Note: As P and b for the first question are not given in the data provided by you. Solved the second…

Q: Ln X = 2.83254 %3D

A: Using formula ln(x) =a x =ea

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A: Solution Given That, Match each P-value with the graph that displays its area without performing any…

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A:

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A: Given:  Evaluate  exponential function.

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A:

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Q: so the answer is 2,420e^-(37/1000)t ?

A:

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A: We have find the amount of particulate matter left in the solution after 5 filtering steps

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A: Recall the formula: ax=b⇔logab=x

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A:

Q: Find the frequency of a musical note which is 5 half-steps above a note with frequency 440 cps.…

A: There are 5 half-steps above a note with frequency 440 cps. That is, n=5,Q0=440.

Q: LN(1 –.70) -100 8

A: So the value of the experience is 9.63.Explanation:

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A: Explanation and solutions is given below....

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A:

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A: We have to find a function f(x) which passes through point (-3,343) and (0,1).

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A:

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A:

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A: It is given that the slope β1 = 1.2.

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A:

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A:

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