Is a statistics class' delivery type a factor in how well students do on the final exam? The table below showsthe average percent on final exams from several randomly selected classes that used the different deliverytypes.Hybrid869084937962Online83566488647182Ho H₁ H2 = μ3H₁: At least two of the means differ from each other.3. The p-value for this sample=4. The p-value is Select an answer5. Base on this, we should [Select an answer6. As such, the final conclusion is that...1. For this study, we should use Select an answer2. The test-statistic for this data =Face-to-Face7197808469Assume that all distributions are normal, the three population standard deviations are all the same, andthe data was collected independently and randomly. Use a level of significance of a = 0.05.9171848076(Please show your answer to 3 decimal places.)(Please show your answer to 4 decimal places.)αhypothesisO There is insufficient evidence to support the claim that course delivery type is a factor in finalexam score.O There is sufficient evidence to support the claim that course delivery type is a factor in finalexam score.

Answered: erage percent on final exams from…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Before the furniture store began its ad campaign, it averaged 117 customers per day. The manager is investigating if the average has changed since the ad came out. The data for the 14 randomly selected days since the ad campaign began is shown below: 85, 114, 96, 124, 110, 121, 90, 115, 127, 116, 117, 110, 84, 129 Assuming that the distribution is normal, what can be concluded at the αα = 0.10 level of significance? For this study, we should use Select an answer z-test for a population proportion t-test for a population mean The null and alternative hypotheses would be: H0:H0: ? μ p Select an answer ≠ = < > H1:H1: ? μ p Select an answer ≠ = > < The test statistic ? t z = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is ? ≤ > αα Based on this, we should Select an answer fail to reject reject accept the null hypothesis.
The length of a movie file that is available for streaming is modeled using the normal distribution shown below. The mean of the distribution is 170.5 min and the standard deviation is 19.9 min, In the figure, V is a number along the axis and is under the highest part of the curve. And, U and W are numbers along the axis that are each the same distance away from V. Use the empirical rule to choose the best value for the percentage of the area under the curve that is shaded, and find the values of U, V, and W. Percentage of total area shaded: (Choose one) 100 120 140 160 180 200 220 240 ( min)
I need a hypothesis, description and interpretation please!! Thanks
Hocument/d/1ho6gSyZTqOTIUok211PsszM1fL7Jz4K2HPR4WWL4x1g/edit sert Format Tools Extensions Help 2 100% D 1 ▼ Normal text 2 1 W L #3 E 2 $ Arial A quality control expert at Glotech computers wants to test their new monitors. The production manager claims they have a mean life of 83 months with a variance of 100. If the claim is true, what is the probability that the mean monitor life would be greater than 81.3 months in a sample of 89 monitors? Round your answer to four decimal places. R % 5 T ^ 10.5 + 6 Y & B 7 * CO I U 5 8 I A ( 9 ) 0 6 P
The Ford car company is interested to know what is fuel consumption rate of its vehicles A large data set, collected in this study, shows that in average cars 11.7 liters per 100 km distance covered. The standard deviation of this value is 1.3 km per 100 km. Assuming that the histogram of this data set is normal, what percent of cars consume between between 10.5 to 11.9 liter of fuel?
Bone mineral density (BMD) is a measure of bone strength. Studies show that BMD declines after age 45. The impact of exercise may increase BMD. A random sample of 59 women between the ages of 41 and 45 with no major health problems were studied. The women were classified into one of two groups based upon their level of exercise activity: walking women and sedentary women. The 39 women who walked regularly had a mean BMD of 5.96 with a standard deviation of 1.22. The 20 women who are sedentary had a mean BMD of 4.41 with a standard deviation of 1.02. Which of the following inference procedures could be used to estimate the difference in the mean BMD for these two types of women
Data from a completely randomized experimental design with three treatments is given below
A random sample of 50 gas stations in Cook County, Illinois, resulted in a mean price per gallon of $2.60 and a standard deviation of $0.07. State the Empirical Rule. A histogram of the data indicates that the data follow a bell-shaped distribution. Use the Empirical Rule to determine the percentage of gas stations that have prices within three standard deviations of the mean. Determine the percentage of gas stations that have prices between $2.46 and $2.74, according to the Empirical Rule. Explain your calculations. Would a gas price of $2.99 be considered unusual in the statistical sense? Why or why not?
Before the furniture store began its ad campaign, it averaged 158 customers per day. The manager is investigating if the average is smaller since the ad came out. The data for the 11 randomly selected days since the ad campaign began is shown below: 147, 142, 149, 133, 146, 159, 132, 137, 148, 172, 150 Assuming that the distribution is normal, what can be concluded at the αα = 0.10 level of significance? For this study, we should use Select an answer z-test for a population proportion t-test for a population mean The null and alternative hypotheses would be: H0:H0: ? μ p Select an answer > ≠ < = H1:H1: ? p μ Select an answer < ≠ > = The test statistic ? z t = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is ? ≤ > αα Based on this, we should Select an answer accept fail to reject reject the null hypothesis. Thus, the final conclusion is that ... The data suggest…
The herbal supplement ginkgo biloba is advertised as producing an increase in physical strength and stamina. To test this claim, a sample of n = 120 adults is obtained and each person is instructed to take the regular daily dose of the herb for a period of 30 days. At the end of the 30 days each person is tested on a standard treadmill task for which the average age-adjusted score is μ = 15. The individuals in the sample produce a mean score of M = 17.4 with SS = 1260. Are these data sufficient to conclude that the herb had a statistically significant effect? Conduct as a two-tailed test, using all hypothesis steps with p < .05. BONUS POINTS: Calculate the 95% confidence interval
17
Which two fields of the ANOVA summary table help us find the critical value? Select all that apply A.df between B.MS within C.df within D. MS between

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