Enter your answer in the provided box. From the following heats of combustion, CH3OH() +02(g) → CO2(g) + 2H,O(1) AH =-726.4 kJ/mol 2 rxn C(graphite) + O2g)→ CO2(g) AH =-393.5 kJ/mol rxn H2(3) + O2(g) H2O(1) AH =-285.8 kJ/mol rxn Calculate the enthalpy of formation of methanol (CH,OH) from its elements:

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Enter your answer in the provided box.
From the following heats of combustion,
CH3OH(1) +,02(3) → CO2(g) + 2H,0(1)
AH
=-726.4 kJ/mol
rxn
C(graphite)+ O2g)→ CO2(g)
ΔΗ
=-393.5 kJ/mol
rxn
H;(g) + 0,(3) →
→ H2O(!)
AH
= -285.8 kJ/mol
rxn
Calculate the enthalpy of formation of methanol (CH,OH) from its elements:
C(graphite) + 2H,(g) +0,() →
→ CH3OH(1)
kJ/mol
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Transcribed Image Text:O Question 17 - Test 1 sem 2_20_2 X O https://ezto.mheducation.com/ext/map/index.html?_con3con&external_browser3D0&launchUrl= Saved 20 21 1 Enter your answer in the provided box. From the following heats of combustion, CH3OH(1) +,02(3) → CO2(g) + 2H,0(1) AH =-726.4 kJ/mol rxn C(graphite)+ O2g)→ CO2(g) ΔΗ =-393.5 kJ/mol rxn H;(g) + 0,(3) → → H2O(!) AH = -285.8 kJ/mol rxn Calculate the enthalpy of formation of methanol (CH,OH) from its elements: C(graphite) + 2H,(g) +0,() → → CH3OH(1) kJ/mol < Prev 17 of 20 NeT arch
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