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Energy of a Bullet Dissipated by Plywood. As part of a criminal investigation, you need to determine how much of a bullet's energy is dissipated by a 0.500-inch piece of plywood. You construct a device that consists of three disks that are separated by a distance d= 0.950 m and rotate on a common axis. The bullet is fired through the first disk (a few inches above its center), which is composed of a light plastic that has a negligible effect on the speed of the bullet. The bullet then passes through the second disk, which is composed of 0.500-inch plywood. Finally, the bullet strikes the third disk, where it becomes embedded. The disks rotate with an angular velocity of w = 80.0 rad/s. The angular displacement between holes. in the first and second disks is A012 = 0.244 rad, and the angular displacement between the holes in the second and third disks is A023 0.262 rad. If the mass of the bullet is 14.0 g, find (a) the initial speed of the bullet and (b) the energy dissipated by the 0.50- inch plywood.

Energy of a Bullet Dissipated by Plywood. As part of a criminal investigation, you need to determine how much of a bullet's energy is dissipated by a 0.500-inch piece of plywood. You construct a device that consists of three disks that are separated by a distance d= 0.950 m and rotate on a common axis. The bullet is fired through the first disk (a few inches above its center), which is composed of a light plastic that has a negligible effect on the speed of the bullet. The bullet then passes through the second disk, which is composed of 0.500-inch plywood. Finally, the bullet strikes the third disk, where it becomes embedded. The disks rotate with an angular velocity of w = 80.0 rad/s. The angular displacement between holes. in the first and second disks is A012 = 0.244 rad, and the angular displacement between the holes in the second and third disks is A023 0.262 rad. If the mass of the bullet is 14.0 g, find (a) the initial speed of the bullet and (b) the energy dissipated by the 0.50- inch plywood.

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Energy of a Bullet Dissipated by Plywood. As part of a criminal investigation, you need to determine how much of a bullet's energy is dissipated by a 0.500-inch piece of plywood. You construct a device that consists of three disks that are separated by a distance d= 0.950 m and rotate on a common axis. The bullet is fired through the first disk (a few inches above its center), which is composed of a light plastic that has a negligible effect on the speed of the bullet. The bullet then passes through the second disk, which is composed of 0.500-inch plywood. Finally, the bullet strikes the third disk, where it becomes embedded. The disks rotate with an angular velocity of w = 80.0 rad/s. The angular displacement between holes. in the first and second disks is A012 = 0.244 rad, and the angular displacement between the holes in the second and third disks is A023 0.262 rad. If the mass of the bullet is 14.0 g, find (a) the initial speed of the bullet and (b) the energy dissipated by the 0.50- inch plywood.
Transcribed Image Text:Energy of a Bullet Dissipated by Plywood. As part of a criminal investigation, you need to determine how much of a bullet's energy is dissipated by a 0.500-inch piece of plywood. You construct a device that consists of three disks that are separated by a distance d= 0.950 m and rotate on a common axis. The bullet is fired through the first disk (a few inches above its center), which is composed of a light plastic that has a negligible effect on the speed of the bullet. The bullet then passes through the second disk, which is composed of 0.500-inch plywood. Finally, the bullet strikes the third disk, where it becomes embedded. The disks rotate with an angular velocity of w = 80.0 rad/s. The angular displacement between holes. in the first and second disks is A012 = 0.244 rad, and the angular displacement between the holes in the second and third disks is A023 0.262 rad. If the mass of the bullet is 14.0 g, find (a) the initial speed of the bullet and (b) the energy dissipated by the 0.50- inch plywood.
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