M Consider the figure above.... A clay block has a mass of 2.6 kg. It rests upon on a friction-less, horizontal surface. The blokc is attached to a rigid rod of length 0.45 m, and of negligible mass. The rod is pivotted at the other end. A bullet of mass 2.7 g traveling parallel to the horizontal surface and perpendicular to the rod with speed 207 m/s hits the block and becomes embedded in it. (a) What is the angular momentum of the bullet/block system about a vertical axis through the pivot? (b) What fraction of the original kinetic energy of the bullet is converted into internal energy in the system during the collision?
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- Consider the frictionless marble-curve track system shown. Marble A is 100.0 g while marble B is 50.0 g. Suppose that both marbles are initially at rest. Right after collision, marble B has a velocity that is three times that of marble A. Ignore air resistance and rotational motion of the marbles. Furthermore, assume that the marbles are much smaller compared to the track.(a) Compute for the total initial mechanical energy associated with the two-marble system with respect to the bottom of the track.(b) Determine the final velocity of each marble after collision assuming that mechanical energy is conserved.(c) Give at least two reasons why in collision between two realistic bodies (that is, not perfectly rigid and with finite macroscopic size), contrary to the assumption in (b) above, mechanical energy is less likely to be conserved even if air resistance and friction can be neglected.A sanding disk with a rotational inertia of 1.2 x 10-3kgm2 is attached to an electric drill whose motor delivers a torque of 16 Nm. If the torque is applied for 25 ms and the disk starts from rest, what is the magnitude of the angular velocity of the sanding disk? Use the rotational version of the Impulse Momentum Theorem. Take note of the time units.As part of a carnival game, a my = 0.653 kg ball is thrown at a stack of 23.8 cm tall, mo = = 0.363 kg objects and hits with a perfectly horizontal velocity of Ubi = 10.8 m/s. Suppose that the ball strikes the topmost object. Immediately after the collision, the ball has a horizontal velocity of bf = 3.10 m/s in the same direction, the topmost object has an angular velocity of @= 1.63 rad/s about its center of mass, and all the remaining objects are undisturbed. Assume that the ball is not rotating and that the effect of the torque due to gravity during the collision is negligible. If the object's center of mass is located r = 16.7 cm below the point where the ball hits, what is the moment of inertia I, of the object about its center of mass? What is the center of mass velocity Uo.cm of the tall object immediately after it is struck? (1) 0 Io = b.J Vo.cm = kg-m² m/s