Your answer is partially correct.Energy of a Bullet Dissipated by Plywood. As part of a criminal investigation, you need to determine how much of a bullet's energy isdissipated by a 0.500-inch piece of plywood. You construct a device that consists of three disks that are separated by a distance d =0.850 m and rotate on a common axis. The bullet is fired through the first disk (a few inches above its center), which is composed of alight plastic that has a negligible effect on the speed of the bullet. The bullet then passes through the second disk, which is composed of0.500-inch plywood. Finally, the bullet strikes the third disk, where it becomes embedded. The disks rotate with an angular velocity ofw = 86.0 rad/s. The angular displacement between holes in the first and second disks is A012 = 0.269 rad, and the angular displacementbetween theholes in the second and third disks is A023 = 0.286 rad.If the mass of the bullet is 12.0 g, find (a) the initial speed of the bullet and (b) the energy dissipated by the 0.50-inch plywood.(a) Number271.82(b) Number i 51.209Unitsm/sUnits JV

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f the mass of the bullet is 12.0 g, find (a) the initial speed of the bullet and (b) the energy dissipated by the 0.50-inch plywood.

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Instantaneous Power

Power is defined in physics as the amount of energy transmitted or transformed per unit time. The watt is the unit of electricity in the International System of Units, equivalent to one joule per second.

Question

Your answer is partially correct.
Energy of a Bullet Dissipated by Plywood. As part of a criminal investigation, you need to determine how much of a bullet's energy is
dissipated by a 0.500-inch piece of plywood. You construct a device that consists of three disks that are separated by a distance d =
0.850 m and rotate on a common axis. The bullet is fired through the first disk (a few inches above its center), which is composed of a
light plastic that has a negligible effect on the speed of the bullet. The bullet then passes through the second disk, which is composed of
0.500-inch plywood. Finally, the bullet strikes the third disk, where it becomes embedded. The disks rotate with an angular velocity of
w = 86.0 rad/s. The angular displacement between holes in the first and second disks is A012 = 0.269 rad, and the angular displacement
between the
holes in the second and third disks is A023 = 0.286 rad.
If the mass of the bullet is 12.0 g, find (a) the initial speed of the bullet and (b) the energy dissipated by the 0.50-inch plywood.
(a) Number
271.82
(b) Number i 51.209
Units
m/s
Units J
V

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