(Electroplating) A steel part with surface area A = 130 cm² is to be tin-plated. What average plating thickness will result if 15 amps are applied for 10 min in an acid sulfate electrolyte bath? The cathode efficiency for tin is E = 90% and the plating constant C = 4.21 x 10-2 mm³/amp-s. V = CIt V = ECIt d = V A Typical cathode efficiencies in electroplating and values of plating constant C. Compiled from [18]. Plate Metal Electrolyte Cadmium (2) Cyanide Chromium (3) Chromium-acid-sulfate Copper (1) Gold (1) Nickel (2) Silver (1) Tin (4) Zinc (2) Cyanide Cyanide Acid sulfate Cyanide Acid sulfate Chloride Plating Constant ca Cathode Efficiency % mm³/amp-s (in³/amp-min) 6.73 × 10-² (2.47 × 10-4) X 2.50 × 10-2 (0.92 × 10-4) (2.69 × 10-4) (3.87 × 10-4) (1.25 × 10-4) (3.90 × 10-4) 90 15 98 80 95 100 90 95 7.35 x 10-2 10.6 x 10-² 3.42 x 10-2 10.7 x 10-2 4.21 x 10-2 4.75 × 10-2 (1.54 x 10-4) (1.74 x 10-4) ¹Most common valence given in parentheses (); this is the value assumed in determining the plating constant C. For a different valence, compute the new C by nultiplying the C' value in the table by the most common valence and then dividing by the new valence.
(Electroplating) A steel part with surface area A = 130 cm² is to be tin-plated. What average plating thickness will result if 15 amps are applied for 10 min in an acid sulfate electrolyte bath? The cathode efficiency for tin is E = 90% and the plating constant C = 4.21 x 10-2 mm³/amp-s. V = CIt V = ECIt d = V A Typical cathode efficiencies in electroplating and values of plating constant C. Compiled from [18]. Plate Metal Electrolyte Cadmium (2) Cyanide Chromium (3) Chromium-acid-sulfate Copper (1) Gold (1) Nickel (2) Silver (1) Tin (4) Zinc (2) Cyanide Cyanide Acid sulfate Cyanide Acid sulfate Chloride Plating Constant ca Cathode Efficiency % mm³/amp-s (in³/amp-min) 6.73 × 10-² (2.47 × 10-4) X 2.50 × 10-2 (0.92 × 10-4) (2.69 × 10-4) (3.87 × 10-4) (1.25 × 10-4) (3.90 × 10-4) 90 15 98 80 95 100 90 95 7.35 x 10-2 10.6 x 10-² 3.42 x 10-2 10.7 x 10-2 4.21 x 10-2 4.75 × 10-2 (1.54 x 10-4) (1.74 x 10-4) ¹Most common valence given in parentheses (); this is the value assumed in determining the plating constant C. For a different valence, compute the new C by nultiplying the C' value in the table by the most common valence and then dividing by the new valence.
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![### Electroplating
A steel part with surface area \( A = 130 \, \text{cm}^2 \) is to be tin-plated. What average plating thickness will result if 15 amps are applied for 10 minutes in an acid sulfate electrolyte bath? The cathode efficiency for tin is \( E = 90\% \) and the plating constant \( C = 4.21 \times 10^{-2} \, \text{mm}^3/\text{amp-s} \).
#### Formulas:
1. \( V = C I t \)
2. \( V = E C I t \)
3. \( d = \frac{V}{A} \)
#### Table: Typical cathode efficiencies in electroplating and values of plating constant \( C \)
_Compiled from [18]._
| Plate Metal\(^{a}\) | Electrolyte | Cathode Efficiency % | Plating Constant \( C^{a} \) |
|---------------------|------------------------|----------------------|------------------------------|
| | | | \(\text{mm}^3/\text{amp-s} \, (\text{in}^3/\text{amp-min})\)|
| Cadmium (2) | Cyanide | 90 | \(6.73 \times 10^{-2} \, (2.47 \times 10^{-4})\) |
| Chromium (3) | Chromium-acid-sulfate | 15 | \(2.50 \times 10^{-2} \, (0.92 \times 10^{-4})\) |
| Copper (1) | Cyanide | 98 | \(7.35 \times 10^{-2} \, (2.69 \times 10^{-4})\) |
| Gold (1) | Cyanide | 80 | \(10.6 \times 10^{-2} \, (3.87 \times 10^{-4})\) |
| Nickel (2) | Acid sulfate | 95 | \(3.42 \times 10^{-2} \, (1.25 \times 10^{-4})\) |
| Silver (1) | Cyanide | 100 | \(10.7 \times 10^{-](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3f8a6c8f-9c9e-4a3f-8cfc-fb848b18acc8%2Fffe65dc1-3a32-48e1-85e3-c25736147a3d%2Fnnddjif_processed.gif&w=3840&q=75)
Transcribed Image Text:### Electroplating
A steel part with surface area \( A = 130 \, \text{cm}^2 \) is to be tin-plated. What average plating thickness will result if 15 amps are applied for 10 minutes in an acid sulfate electrolyte bath? The cathode efficiency for tin is \( E = 90\% \) and the plating constant \( C = 4.21 \times 10^{-2} \, \text{mm}^3/\text{amp-s} \).
#### Formulas:
1. \( V = C I t \)
2. \( V = E C I t \)
3. \( d = \frac{V}{A} \)
#### Table: Typical cathode efficiencies in electroplating and values of plating constant \( C \)
_Compiled from [18]._
| Plate Metal\(^{a}\) | Electrolyte | Cathode Efficiency % | Plating Constant \( C^{a} \) |
|---------------------|------------------------|----------------------|------------------------------|
| | | | \(\text{mm}^3/\text{amp-s} \, (\text{in}^3/\text{amp-min})\)|
| Cadmium (2) | Cyanide | 90 | \(6.73 \times 10^{-2} \, (2.47 \times 10^{-4})\) |
| Chromium (3) | Chromium-acid-sulfate | 15 | \(2.50 \times 10^{-2} \, (0.92 \times 10^{-4})\) |
| Copper (1) | Cyanide | 98 | \(7.35 \times 10^{-2} \, (2.69 \times 10^{-4})\) |
| Gold (1) | Cyanide | 80 | \(10.6 \times 10^{-2} \, (3.87 \times 10^{-4})\) |
| Nickel (2) | Acid sulfate | 95 | \(3.42 \times 10^{-2} \, (1.25 \times 10^{-4})\) |
| Silver (1) | Cyanide | 100 | \(10.7 \times 10^{-
Expert Solution
Step 1
I = 12 + 0.2t
After time, 't', Next infinitly small time 'dt' let heat deposited 'dQ'
∴ dQ = 2.50 × 10-2 (mm3/A.s) × 12 + 0.2t × dt
As we have to convert this 's' to 'min'
∴ dQ = 2.50 × 10-2 (mm3/A × min) × 12 + 0.2t × dt
Considering cathode efficiency of 15%
dQ = 2.50 × 10-2 × 60 × (12 + 0.2t)dt × 0.15 mm3
∴ In 20 min, 2.50 × 10-2 × 60 × (12 + 0.2t)dt × 0.15
= 0.225[12 × 20 + 0.1 × 202] mm3
= 63 mm3
As area os 125 cm2
Plating thickness,
t = 63 / 125 * (100)
= 0.00504 mm = 5.04 mio m
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