Electronics Circuit: BJT biasing A Voltage Divider bias NPN BJT (Beta = 80) circuit is connected to a 16VDC supply with the following components R1= 62 KOhms, R2= 9.1 KOhms, Rc= 3.9 KOhms, and Re= 0.68 KOhms. Determine the Base Voltage (Vb). а. 1.86 Volts b. 1.16 Volts с. 9.33 Volts d. 8.17 Volts

Electronics Circuit: BJT biasing A Voltage Divider bias NPN BJT (Beta = 80) circuit is connected to a 16VDC supply with the following components R1= 62 KOhms, R2= 9.1 KOhms, Rc= 3.9 KOhms, and Re= 0.68 KOhms. Determine the Base Voltage (Vb). а. 1.86 Volts b. 1.16 Volts с. 9.33 Volts d. 8.17 Volts

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

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Question

Electronics Circuit: BJT biasing
A Voltage Divider bias NPN BJT (Beta = 80) circuit is
connected to a 16VDC supply with the following
components R1= 62 KOhms, R2= 9.1 KOhms, Rc= 3.9
KOhms, and Re= 0.68 KOhms. Determine the Base
Voltage (Vb).
а.
1.86 Volts
b.
1.16 Volts
с.
9.33 Volts
d.
8.17 Volts

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