For a single-phase half wave-controlled rectifier with RL load, use the chartbelow to find the commutation angle ß for the following cases1) (a=40°, 0=15° then ß=)2) (a=80°, 0 =0° then B=)3) (α =100°, 0 =45° then =)4) (a=120°, 0=75° then ß=180°Conduction Angle (0)160°140°120°10080°60%40%20°0°p=0$=156=30++20° 40° 60°X6=75$9080°100 120°Delay Angle (0)140⁰ 160°180°

A single-phase half-wave rectifier with resistor and inductor load is a circuit build-up of…

For a single-phase half wave-controlled rectifier with RL load, use the chart below to find the commutation angle ß for the following cases 1) (a=40⁰, 0 =15° then ß= ) 2) (α =80⁰, 0 =0° then ß= ) 3) (a=100⁰, 0 =45° then = ) 4) (a=120°, 0=75⁰ then B= 180° Conduction Angle (0) 160° 140° 120- 100 80° 60 40- 20 0° $3 20° 6=30 40⁰° 60° ) X6=75 90 + + 80° 100 120° Delay Angle (a) 140 160 180

For a single-phase half wave-controlled rectifier with RL load, use the chart below to find the commutation angle ß for the following cases 1) (a=40⁰, 0 =15° then ß= ) 2) (α =80⁰, 0 =0° then ß= ) 3) (a=100⁰, 0 =45° then = ) 4) (a=120°, 0=75⁰ then B= 180° Conduction Angle (0) 160° 140° 120- 100 80° 60 40- 20 0° $3 20° 6=30 40⁰° 60° ) X6=75 90 + + 80° 100 120° Delay Angle (a) 140 160 180

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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