[Elastic Properties of Materials] There is a cylindrical bar of copper do in diameter is to be deformed elastically by application of a force along the bar axis. Using the data in Table given below, determine the normal force (F) that will produce an elastic reduction of Ad in the diameter. Use do 12.0 mm; Ad = d' - do = -3 x 10-³mm =

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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[Elastic Properties of Materials] There is a cylindrical bar of copper do in diameter is to be deformed elastically
by application of a force along the bar axis. Using the data in Table given below, determine the normal force (F)
that will produce an elastic reduction of Ad in the diameter.
Use do
12.0 mm; Ad = d' - do = -3 × 10-³mm
x
=
do
1
F
d'
l'
Metal Alloy
Aluminum
Brass
Copper
Magnesium
Nickel
Steel
Titanium
Tungsten
Modulus of
Elasticity
GPa
69
97
110
45
207
207
107
407
106 psi
10
14
16
6.5
30
30
15.5
59
Shear Modulus
106 psi
GPa
25
37
46
17
76
83
45
160
3.6
5.4
6.7
2.5
11.0
12.0
6.5
23.2
Poisson's Ratio
0.33
0.34
0.34
0.29
0.31
0.30
0.34
0.28
Transcribed Image Text:[Elastic Properties of Materials] There is a cylindrical bar of copper do in diameter is to be deformed elastically by application of a force along the bar axis. Using the data in Table given below, determine the normal force (F) that will produce an elastic reduction of Ad in the diameter. Use do 12.0 mm; Ad = d' - do = -3 × 10-³mm x = do 1 F d' l' Metal Alloy Aluminum Brass Copper Magnesium Nickel Steel Titanium Tungsten Modulus of Elasticity GPa 69 97 110 45 207 207 107 407 106 psi 10 14 16 6.5 30 30 15.5 59 Shear Modulus 106 psi GPa 25 37 46 17 76 83 45 160 3.6 5.4 6.7 2.5 11.0 12.0 6.5 23.2 Poisson's Ratio 0.33 0.34 0.34 0.29 0.31 0.30 0.34 0.28
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