Problem 2. A block of cast iron was wrapped in the thin aluminum foil as shown on the figure. At room temperature there is no stress on the foil. The whole system is then immersed in liquid nitrogen at -196°C. Find the stress on the aluminum foil. Is the foil going to deform permanently? Is it going to break? Stress [MPa] 350 300 250- 200 150 100- 50 0 0 alu alloy 5083-H34. 0.005 0.01 0.015 0.02 Strain Aluminum foil 5 µm thick, this is a continuous strip with the ends welded together Cast iron 20 mm thick a aluminum = 2.4 105 K-1, Stress MPa 400 300 200 100 a iron 1.2 10-5 K-1 It 11 0 0 0.05 0.1 0.15 0.2 0.25 Strain Fig. 2. Stress-strain diagrams for aluminum. Left: Low strain region. Right: Full strain range. Hint: you can get the Young's modulus, proportions limit (elastic limit), and break point from the graphs.
Problem 2. A block of cast iron was wrapped in the thin aluminum foil as shown on the figure. At room temperature there is no stress on the foil. The whole system is then immersed in liquid nitrogen at -196°C. Find the stress on the aluminum foil. Is the foil going to deform permanently? Is it going to break? Stress [MPa] 350 300 250- 200 150 100- 50 0 0 alu alloy 5083-H34. 0.005 0.01 0.015 0.02 Strain Aluminum foil 5 µm thick, this is a continuous strip with the ends welded together Cast iron 20 mm thick a aluminum = 2.4 105 K-1, Stress MPa 400 300 200 100 a iron 1.2 10-5 K-1 It 11 0 0 0.05 0.1 0.15 0.2 0.25 Strain Fig. 2. Stress-strain diagrams for aluminum. Left: Low strain region. Right: Full strain range. Hint: you can get the Young's modulus, proportions limit (elastic limit), and break point from the graphs.
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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![Problem 2. A block of cast iron was wrapped in the thin aluminum foil as shown on the figure. At
room temperature there is no stress on the foil. The whole system is then immersed in liquid
nitrogen at -196°C. Find the stress on the aluminum foil. Is the foil going to deform
permanently? Is it going to break?
Stress [MPa]
350
300
250
200
150
100
50
0
0
alu alloy
5083-H34
0.005 0.01 0.015 0.02
Strain
Aluminum foil 5 µm thick, this is a continuous strip with
the ends welded together
Cast iron 20 mm thick
a aluminum = 2.4 105 K-¹,
Stress MPa
400
300
200
100
a iron 1.2 105 K-1
↑
11
0
0 0.05 0.1 0.15 0.2 0.25
Strain
Fig. 2. Stress-strain diagrams for aluminum. Left: Low strain region. Right: Full strain range. Hint:
you can get the Young's modulus, proportions limit (elastic limit), and break point from the
graphs.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4ae89d13-3da3-4f42-8a30-4752fc9f6b5c%2F9b916d56-93e6-4672-a3be-a6c1da01ba7a%2F4mhyz7h_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Problem 2. A block of cast iron was wrapped in the thin aluminum foil as shown on the figure. At
room temperature there is no stress on the foil. The whole system is then immersed in liquid
nitrogen at -196°C. Find the stress on the aluminum foil. Is the foil going to deform
permanently? Is it going to break?
Stress [MPa]
350
300
250
200
150
100
50
0
0
alu alloy
5083-H34
0.005 0.01 0.015 0.02
Strain
Aluminum foil 5 µm thick, this is a continuous strip with
the ends welded together
Cast iron 20 mm thick
a aluminum = 2.4 105 K-¹,
Stress MPa
400
300
200
100
a iron 1.2 105 K-1
↑
11
0
0 0.05 0.1 0.15 0.2 0.25
Strain
Fig. 2. Stress-strain diagrams for aluminum. Left: Low strain region. Right: Full strain range. Hint:
you can get the Young's modulus, proportions limit (elastic limit), and break point from the
graphs.
Expert Solution
Step 1
Solution:
Given Data:
*The initial stress in the foil,
*The temperature of the Nitrogen is,
*The thickness of the aluminium foil is,
*The thermal expansion coefficient of the aluminium is,
*The thermal expansion coefficient of the cast iron is,
*The thickness of the cast iron is,
To Find:
(a) Stress value in the aluminium foil after the immersion, ?
(b) Is the foil going to deform permanently or break?
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