Answered: Elaine wears her wide-brimmed hat at… | bartleby

Related questions

Question

Elaine wears her wide-brimmed hat at the beach, where the atmospheric pressure is exactly 1.0 atm.

Determine the weight \( w \) of the imaginary column of air that "rests" on her hat if its diameter is 43 cm.

\[ w = \, \boxed{\phantom{answer}} \, \text{N} \]

Expert Solution

Trending now

This is a popular solution!

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Blurred answer

Similar questions

I got 680 N is this correct?
What is the pressure inside the drop of mercury of radius 3.00 mm at room temperature? Surface tension of mercury at that temperature (20°C) is 4.65 x 10 N m. The atmospheric pressure is 1.01 x 10° Pa. Also give the excess pressure inside the drop.
Dr. B uses his phone and the app phyphox to measure atmospheric pressure at different heights. At the first floor of the UMass W.E.B. DuBois Library he measures a pressure of 101300 Pa. He then takes the elevator to the roof of the library and measures a pressure of 100172 Pa. If the density of the air is 1.205kg/m33, what is the height of the library? a. 124 m b. 96 m c. 76 m d. 67 m e. 105 m
Which of the following is true for the situation below? po is the atmospheric pressure, p is the density of the mercury. Pgas - Mercury 16 cm 6 ст Pgas = PO Pgas + Pg(0.06m) = PO Pgas = Po + pg(0.10m) Pgas = Po + pg(0.16m) O Pgas + Pg(0.10m) = Po %3D pgas + pg(0.16m) = Po Pgas = Po + pg(0.06m)
Tire gauges for air pressure, as well as most other gauges used in an industrial environment take into account the pressure due to the atmosphere of earth. That's why your car gauge reads 0 before you put it on your tire to check your pressure. That is called gauge pressure. The real pressure within a tire or other object contains pressurized stuff would be a combination of what the gauge reads as well at the atmospheric pressure. If a gauge on a tire reads 40.16 psi, what is the real pressure in the tire in pascals. The atmospheric pressure is 1.01x10^5 Pa.
The height of mercury in a barometer is measured at 85.0 cm. Compute for the atmospheric pressure.
Problem 1: A certain rigid aluminum container contains a liquid at a gauge pressure of P0 = 2.02 × 105 Pa at sea level where the atmospheric pressure is Pa = 1.01 × 105 Pa. The volume of the container is V0 = 2.15 × 10-4 m3. The maximum difference between the pressure inside and outside that this particular container can withstand before bursting or imploding is ΔPmax = 2.41 × 105 Pa.For this problem, assume that the density of air maintains a constant value of ρa = 1.20 kg / m3 and that the density of seawater maintains a constant value of ρs = 1025 kg / m3. What is the maximum depth dmax in meters below the surface of the ocean that the container can be taken before imploding?