A certain rigid aluminum container contains a liquid at a gauge pressure equal to P0 = 2.02 × 105 Pa at sea level where the atmospheric pressure Pa = 1.01 × 105 Pa. The volume of the container is V0 = 2.9 × 10-4 m3. The maximum difference between the pressure inside and outside the container that this particular container can withstand before bursting or imploding is ΔP = 2.43 × 105 Pa.For this problem, assume that the density of air maintains a constant value of ρa = 1.20 kg / m3 and that the density of seawater maintains a constant value of ρs = 1025 kg / m3. ΔP = 2.43 × 105 PaV0 = 2.9 × 10-4 m3 a)The container is taken from sea level, where the pressure of air is Pa = 1.01 × 105 Pa, to a higher altitude. What is the maximum height h in meters above the ground that the container can be lifted before bursting? Neglect the changes in temperature and acceleration due to gravity with altitude. b)What is the maximum depth h in meters below the surface of the ocean that the container can be taken before imploding?
Viscosity
The measure of the resistance of a fluid to flow is known as viscosity. Most fluids have some resistance to motion, the resistance provided by the fluid is called viscosity. This resistance is created by the force of attraction between the fluid molecules. If you pour water through a funnel, it flows easily and quickly, because it has very little resistance. But if you pour honey through a funnel, it may take a little time longer, as the density of honey is high.
Poiseuille's Law
The law of Poiseuille or Poiseuille's equation states that the pressure drop of an incompressible fluid especially a liquid in a laminar flow that passes through a cylindrical tube of length L, radius r, pressure gradient ΔP, and mainly depends on the viscosity of the fluid is nothing but the pressure difference of the layers of fluids. ΔP=P1-P2
Drag Forces
Forces that occur due to the movement of fluid are known as fluid mechanics. Following are the fluids present:
A certain rigid aluminum container contains a liquid at a gauge pressure equal to P0 = 2.02 × 105 Pa at sea level where the atmospheric pressure Pa = 1.01 × 105 Pa. The volume of the container is V0 = 2.9 × 10-4 m3. The maximum difference between the pressure inside and outside the container that this particular container can withstand before bursting or imploding is ΔP = 2.43 × 105 Pa.
For this problem, assume that the density of air maintains a constant value of ρa = 1.20 kg / m3 and that the density of seawater maintains a constant value of ρs = 1025 kg / m3.
ΔP = 2.43 × 105 Pa
V0 = 2.9 × 10-4 m3
a)The container is taken from sea level, where the pressure of air is Pa = 1.01 × 105 Pa, to a higher altitude. What is the maximum height h in meters above the ground that the container can be lifted before bursting? Neglect the changes in temperature and acceleration due to gravity with altitude.
b)What is the maximum depth h in meters below the surface of the ocean that the container can be taken before imploding?
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