EDTA is a hexaprotic system with the pKa values: FOOC-CH2 H2C-COO pKal = 0.00, pK22 = 1.50, pK23 = 2.00, pK24 = 2.69, pKa5 6.13, and pKa6 = 10.37. :N-CH2-CH2-N: 0OC-CH2 H2C-coo The distribution of the various protonated forms of EDTA EDTA4- (or Y4-) will therefore vary with pH. For equilibrium calculations involving metal complexes with EDTA, it is convenient to calculate the fraction of EDTA that is in the completely unprotonated form, Y*-. This fraction is designated aya-. Calculate ay4- at two pH values. pH = 3.85 dy4- = pH = 10.80 dyt- =

EDTA is a hexaprotic system with the pKa values: FOOC-CH2 H2C-COO pKal = 0.00, pK22 = 1.50, pK23 = 2.00, pK24 = 2.69, pKa5 6.13, and pKa6 = 10.37. :N-CH2-CH2-N: 0OC-CH2 H2C-coo The distribution of the various protonated forms of EDTA EDTA4- (or Y4-) will therefore vary with pH. For equilibrium calculations involving metal complexes with EDTA, it is convenient to calculate the fraction of EDTA that is in the completely unprotonated form, Y*-. This fraction is designated aya-. Calculate ay4- at two pH values. pH = 3.85 dy4- = pH = 10.80 dyt- =

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

EDTA is a hexaprotic system with the pKa values:
FOOC-CH2
H2C-CoO
pKal = 0.00, pK22 = 1.50, pK23 = 2.00, pK4 = 2.69,
2.00, рКа4
:N-CH2-CH2-N:
%3D
%D
pK25 =
6.13, and pKa6 = 10.37.
%3D
0OC-CH2
H,C-co
The distribution of the various protonated forms of EDTA
EDTA4- (or Y4-)
will therefore vary with pH. For equilibrium calculations
involving metal complexes with EDTA, it is convenient to
calculate the fraction of EDTA that is in the completely
unprotonated form, Y*-. This fraction is designated ay4- .
Calculate ay4- at two pH values.
pH = 3.85
%3D
dy4- =
pH = 10.80
%3D
dy4- =

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