EDTA is a hexaprotic system with the pKa values: FOOC-CH2 H2C-COO pKal = 0.00, pK22 = 1.50, pK23 = 2.00, pK24 = 2.69, pKa5 6.13, and pKa6 = 10.37. :N-CH2-CH2-N: 0OC-CH2 H2C-coo The distribution of the various protonated forms of EDTA EDTA4- (or Y4-) will therefore vary with pH. For equilibrium calculations involving metal complexes with EDTA, it is convenient to calculate the fraction of EDTA that is in the completely unprotonated form, Y*-. This fraction is designated aya-. Calculate ay4- at two pH values. pH = 3.85 dy4- = pH = 10.80 dyt- =

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
icon
Related questions
Question
EDTA is a hexaprotic system with the pKa values:
FOOC-CH2
H2C-CoO
pKal = 0.00, pK22 = 1.50, pK23 = 2.00, pK4 = 2.69,
2.00, рКа4
:N-CH2-CH2-N:
%3D
%D
pK25 =
6.13, and pKa6 = 10.37.
%3D
0OC-CH2
H,C-co
The distribution of the various protonated forms of EDTA
EDTA4- (or Y4-)
will therefore vary with pH. For equilibrium calculations
involving metal complexes with EDTA, it is convenient to
calculate the fraction of EDTA that is in the completely
unprotonated form, Y*-. This fraction is designated ay4- .
Calculate ay4- at two pH values.
pH = 3.85
%3D
dy4- =
pH = 10.80
%3D
dy4- =
Transcribed Image Text:EDTA is a hexaprotic system with the pKa values: FOOC-CH2 H2C-CoO pKal = 0.00, pK22 = 1.50, pK23 = 2.00, pK4 = 2.69, 2.00, рКа4 :N-CH2-CH2-N: %3D %D pK25 = 6.13, and pKa6 = 10.37. %3D 0OC-CH2 H,C-co The distribution of the various protonated forms of EDTA EDTA4- (or Y4-) will therefore vary with pH. For equilibrium calculations involving metal complexes with EDTA, it is convenient to calculate the fraction of EDTA that is in the completely unprotonated form, Y*-. This fraction is designated ay4- . Calculate ay4- at two pH values. pH = 3.85 %3D dy4- = pH = 10.80 %3D dy4- =
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 4 steps with 2 images

Blurred answer
Similar questions
Recommended textbooks for you
Chemistry
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education
Principles of Instrumental Analysis
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
Organic Chemistry
Organic Chemistry
Chemistry
ISBN:
9780078021558
Author:
Janice Gorzynski Smith Dr.
Publisher:
McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning
Elementary Principles of Chemical Processes, Bind…
Elementary Principles of Chemical Processes, Bind…
Chemistry
ISBN:
9781118431221
Author:
Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:
WILEY