each week is 1.3. The study found that for a sample of 2549 teenagers the mean number of softdrinks consumed per week is 5.4 . Construct the desired confidence interval round your answers to one decimal place.

Q: The standard deviation of the weights of elephants is known to be approximately 15 pounds. We wish…

A: Answer  Given  Sample mean =244 population standard deviation=15 sample size =50 Confidence interval…

Q: You are interested in finding a 95% confidence interval for the mean number of visits for physical…

A: Given,mean(x¯)=13.6standard deviation (s)=9.1918sample size(n)=10degrees of…

Q: Suppose we are interested to construct a confidence interval of the mean exam score. A random sample…

A:

Q: survey to determine if the percentage of adults who use social media has changed from 52%, which was…

A: The sample proportion is computed as follows, The critical value for 96% confidence level, i.e.,…

Q: Suppose we are interested to construct a confidence interval at 95% confidence level of the mean…

A: The provided information is  α=0.05 The critical value is  zc=1.96  (from standard normal table) The…

Q: You are given the sample mean and the population standard deviation. Use this information to…

A: Given Data: Confidence level - 90%: The expression for the confidence level is,

Q: A survey of college students reported that in a sample of 41 male college students, the average…

A: From the provided information,

Q: If r = 0.7 for the probability and statistics course grades of 30 students, construct a 95%…

A: Confidence interval for correlation coefficient is given by,

Q: A researcher wanted to check whether the percentage of Canadian adults with obesity has decreased in…

A: Number of Canadian adults in 2005= 75 Number of Canadian adults in 2009 = 120   significance level =…

Q: An admission officer of a small liberal arts college wishes to compare the mean admission test…

A: Given: n1= 15 ,x̄1= 495.0 ,s1= 55.0 n2= 17 ,x̄2= 545.0 ,s2= 50.0 At 95.0 % confidence level with…

Q: information to complete parts a through d below coefficient was used to generate the confidence…

A:

Q: Justin is interested in buying a digital phone. He visited 14 stores at random and recorded the…

A: Solution 95% confidence interval for the mean price of this model of digital phone $302.478 to…

Q: How much more likely are college men than college women to participate in intramural sports?  A…

A: Given information: Number of college men surveyed, n1=688 Number of college women surveyed, n2=579…

Q: Which of the following describes the function of a confidence interval? Select one: a. It uses a…

A: Given Options, a. It uses a sample mean to estimate the population mean b. It uses a population mean…

Q: Suppose you wanted to take another sample of dogs to find a 90% confidence interval of young dogs to…

A:

Q: Construct a 95% confidence interval for the mean time to prepare a tax return. In the next…

A:

Q: Work Time Lost due to Accidents At a large company, the Director of Research found that the average…

A:

Q: Student advisors are interested in determining if the variances of the scores of day students and…

A: Student advisors are interested in determining if the variances of scores of day students and night…

Q: The 92 million Americans of age 50 and over control 50% of all discretionary income. AARP estimates…

A: The margin of error is given by the formula: MoE=z×σn=1.96×55080=120.52

Q: Javier wants to estimate the percentage of people who have purchased a used car. He surveys 250…

A: From the provided information, Sample size (n) = 250 From which 212 have purchased a used car.…

Q: Here are summary statistics for randomly selected weights of newborn girls: n = 250, x= 32.4 hg, s=…

A: The following information has been provided: The sample size is n=20. The sample mean is x¯=32.5.…

Q: A student read that a 95% confidence interval for the mean age an American first drinks alcohol is…

A: Lower limit = 16 - 1.2 =14.8 Lower limit = 16 + 1.2 =17.2

Q: You measure 29 backpacks' weights, and find they have a mean weight of 46 ounces. Assume the…

A:

Q: You are interested in estimating the the mean weight of the local adult population of female…

A: Given that the population standard deviation is 17 pounds. Confidence level is 96% Margin of error…

Q: A recent study of 25 students showed that they spend an average of $18.53 for gas per week. The…

A: Given: Sample size n = 25 Sample mean X = 18.53 Sample standard deviation s = 3

Q: a. Find the best point estimate of the mean. b. Find the 95% confidence interval of the mean score…

A: According to the answering guidelines, we can answer only three subparts of a question and the rest…

Q: You measure 22 backpacks' weights, and find they have a mean weight of 39 ounces. Assume the…

A: The independent variable is backpacks' weight. The sample size is 22. The sample mean is 39 ounces.…

Q: A toy manufacturer wants to know how many new toys children buy each year. A sample of 242 children…

A:

Q: You measure 33 dogs' weights, and find they have a mean weight of 55 ounces. Assume the population…

A: It is given that Sample size n = 33 Sample mean M = 55 Population SD = 14 The critical value of Z at…

Q: You measure 24 turtles' weights, and find they have a mean weight of 34 ounces. Assume the…

A:

Q: Suppose we want a 99% confidence interval for the average amount spent on books by freshmen in their…

A: Standard Deviation = σ = 31 Margin of Error = E = 3 Confidence Level = 99 Significance Level =…

Q: Express the form of most of the confidence intervals that you will encounter in your study of…

A: Confidence Interval:Confidence interval is the interval estimate of the population parameter. It is…

Q: A random sample of high school students

A: Here it is given that, A 99% confidence interval based on this sample is 1.7 hours to 3.1 hours

Q: Collette is self-employed, selling items at Home Interior parties. She wants to estimate the average…

A: Given: Sample size (n) = 35 Sample mean x¯=34.70 Population standard deviation σ=4.85 Confidence…

Q: you take a sample in equal 25 of test scores from a population. The sample mean is 38, and the…

A:

Q: poll reported that only 645 out of a total of 2029 adults in a particular region said they had a​…

A: According to the given information in this question We need to construct 80% confidence interval

Q: A new drug to treat high cholesterol is being tested by pharmaceutical company. The cholesterol…

A: Mean difference (M) = 15.91 mg/dL Standard deviation of the mean difference (s) = 15.2714 mg/dL…