The 92 million Americans of age 50 and over control 50% of all discretionary income. AARP estimates that the average annual expenditure on restaurants and carryout food was $1873 for individuals in this age group. Suppose this estimate is based on a sample of 80 persons and that the sample standard deviation is $550. We want to develop a 95% confidence interval for the population mean. The margin of error is The margin of error is how many dollars? The standard error is The upper bound of this 95% confidence interval is The lower bound of this 95% confidence interval is
The 92 million Americans of age 50 and over control 50% of all discretionary income. AARP estimates that the average annual expenditure on restaurants and carryout food was $1873 for individuals in this age group. Suppose this estimate is based on a sample of 80 persons and that the sample standard deviation is $550. We want to develop a 95% confidence interval for the population mean. The margin of error is The margin of error is how many dollars? The standard error is The upper bound of this 95% confidence interval is The lower bound of this 95% confidence interval is
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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The 92 million Americans of age 50 and over control 50% of all discretionary income. AARP estimates that the average annual expenditure on restaurants and carryout food was $1873 for individuals in this age group. Suppose this estimate is based on a sample of 80 persons and that the sample standard deviation is $550. We want to develop a 95% confidence interval for the population mean.
The margin of error is
The margin of error is how many dollars?
The standard error is
The upper bound of this 95% confidence interval is
The lower bound of this 95% confidence interval is
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