e following relation describes the volume change in a water (solvent – species 1) and salt (solute – species 2) solution: V=1.001+16.625n2 +56.092 n23/2 +119.4n22 where V is expressed in units of liters, and n2 in kmole. (1) Obtain an expression for partial V2 in terms of n2, and determine partial V2 when x2 is approching 0 in liter per kmole. (2) Obtain an expression for partial V1 one in terms of n2, and one in terms of x1
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e following relation describes the volume change in a water (solvent – species 1) and salt (solute – species 2) solution:
V=1.001+16.625n2 +56.092 n23/2 +119.4n22
where V is expressed in units of liters, and n2 in kmole.
(1) Obtain an expression for partial V2 in terms of n2, and determine partial V2 when x2 is approching 0 in liter per kmole.
(2) Obtain an expression for partial V1 one in terms of n2, and one in terms of x1
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- The following relation describes the volume change in a water (solvent – species 1) and salt (solute – species 2) solution: V=1.001+16.625n2 +56.092 n23/2 +119.4n22 where V is expressed in units of liters, and n2 in kmole. (1) Obtain an expression for partial V2 in terms of n2, and determine partial V2 when x2 is approching 0 in liter per kmole. (2) Obtain an expression for partial V1 one in terms of n2, and one in terms of x1.Osmotic pressures are often reported in units of atmospheres or mm Hg. The latter impliesthat the height of a column of liquid can be used as a measure of pressure. This is, in fact, thebasis of the torricellian barometer from which the units of “torr” come. The pressure, P, isrelated to the height of the column by:P = ρghwhere ρ is the density of the liquid, g is the acceleration due to gravity and h is the height. Whatwill be the height (in mm) of a column of aqueous solution with a density of 0.9987 g/mL, if theosmotic pressure of the solution at 25 °C is 1.4 mm Hg? The density of mercury at thistemperature is 13.8 g/mLPhenol and water form non-ideal liquid mixtures. When 7.32 g of phenol and 7.95 g of water are mixed together at 60 °C they form two immiscible liquid phases with mole fractions of phenol of 0. 0 42 and 0 .161 . (a) Calculate the overall mole fraction of phenol in the mixture. (b) Use the lever rule to determine the relative amounts of the two phases .
- At 39.9 ◦C, a mixture of ethanol (x1 = 0.9060, p1 = 130.4 Torr) and isooctane ( p2 = 43.9 Torr) forms a vapor phase with molar fraction y1 = 0.6667 at a total pressure of 185.9 Torr. (a) Calculate the activity and activity coefficient of each component. (b) Calculate the total vapor pressure that the mixture would have if it were ideal.b) Suppose you had a solution of 6.84 g of sugar (sucrose, C12HO1) in 90.0 g of water. (i) Calculate the number of moles of sugar and water present. (H=1; C=12; 0=16) (ii) Calculate the mole fraction of the water in the solution. (iii) At 100°C, the saturated vapour pressure of water at its boiling point is 101325 Pa. Calculate the vapour pressure of the solution at that temperature. (Remember to give your answer to a suitable number of significant figures.) (iv) Would the solution of sugar in water boil at this temperature, assuming the external pressure remains at 101325 Pa? Explain your answer.Phenol and water form non-ideal liquid mixtures. When 7.32 g of phenol and 7.95 g of water are mixed together at 60 °C they form two immiscible liquid phases with mole fractions of phenol of 0.042 and 0.161. (i) Calculate the overall mole fraction of phenol in the mixture. (ii) Use the lever rule to determine the relative amounts of the two phases.
- The sealed containers of fizzy drinks contain dissolved CO2. This dissolved CO2 is in equilibrium with a small quantity of gaseous CO2 at the top of the container. (a) The partial pressure of CO2 gas in a 250 cm3 can of fizzy drink is 3.0 atm at 25 0C. What is the concentration of CO2 in the fizzy drink? (b) If the can contain only the mass of CO2 1.09g as a gas, calculate the pressure in the can when it is stored at 25 0C. (c) The maximum pressure that a can of fizzy drink can withstand is 7 atm. Using the graph below, determine the maximum temperature at which a can, can be stored safely. (concentration=0.093MAniline, C6H5NH2, and hexane, C6H14, form partially miscible liquid–liquid mixtures at temperatures below 69.1 °C. When 42.8 g of aniline and 75.2 g of hexane are mixed together at a temperature of 67.5 °C, two separate liquid phases are formed, with mole fractions of aniline of 0.308 and 0.618. (i) Determine the overall mole fraction of aniline in the mixture. (ii) Use the lever rule to determine the relative amounts of the two phases.Dibromoethene (DE, p*DE = 22.9 kPa at 358 K) and dibromopropene (DP, p*DP = 17.1 kPa at 358 K) form a nearly ideal solution. If zDE = 0.60, what is (a) ptotal when the system is all liquid, (b) the composition of the vapour when the system is still almost all liquid.
- The partial molar volumes of water and ethanol in a solution with H₂O = 0.45 at 25 °C are 17.0 and 57.0 cm³ mol-¹, respectively. -1 Part A AV = Calculate the volume change upon mixing sufficient ethanol with 8.20 mol of water to give this concentration. The densities of water and ethanol are 0.997 and 0.7893 g cm 5, respectively, at this temperature. Express your answer to two significant figures and include the appropriate units. Submit μÅ Value Request Answer Units Review | Constants I Periodic Table . ?The sealed containers of fizzy drinks contain dissolved CO2. This dissolved CO2 is in equilibrium with a small quantity of gaseous CO2 at the top of the container. (a) The partial pressure of CO2 gas in a 250 cm3 can of fizzy drink is 3.0 atm at 25 0C. What is the concentration of CO2 in the fizzy drink? (b) If the can contain only the mass of CO2 calculated in part (ii) as a gas, calculate the pressure in the can when it is stored at 25 0C. (c) The maximum pressure that a can of fizzy drink can withstand is 7 atm. Using the graph below, determine the maximum temperature at which a can, can be stored safely. (concentration=0.093M)Show that (demonstrate) for an ideal binary solution, where 1 is the solvent and 2 is the solute, the increase in the boiling point of the solvent (ΔT) due to the presence of the solute is given by the relation: ∆T=Kebb2=(T'eb-Teb) where Keb=[R(Teb)2M1]/1000∆vapH1] Keb=ebulloscopic constant Please show all of the steps and calculations used to demonstrate the question. As well as a brief explanation of the principle used.