Decide whether each of the molecules in the table below is stable, in the exact form in which it is drawn, at pH = 11.If you decide at least one molecule is not stable, then redraw one of the unstable molecules in its stable form below the table. (If more than one molecule isunstable, you can pick any of them to redraw.)HOOstableOunstableOstableOunstableOHOstableOstableOunstableOunstableOHAm5

Answered: Decide whether each of the molecules in…

Organic Chemistry: A Guided Inquiry

2nd Edition

ISBN:9780618974122

Author:Andrei Straumanis

Publisher:Andrei Straumanis

Chapter5: Resonance

Section: Chapter Questions

Problem 2CTQ: You will not find “hydroxide” in the stockroom, but you will find sodium hydroxide (NaOH)...

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Compound ∆Hf (kJ/mole) ∆S (J/mole K) C2H4 52.4 219.3 C2H6 –84.68 229.2 SiO2 –910.7 41.5 HF –273.3 173.8 SiF4 –1615.0 282.8 NH3 –45.9 192.9 O2 1.88 2.43 NO 91.3 210.8 H2O(g) –241.8 188.8 For the following reactions, using the provided ∆H and ∆S data, determine whether each one would be spontaneous or nonspontaneous at 25°C. C2H4(g) + H2(g) --------à C2H6(g) SiO2 + 4 HF(g) -------------> SiF4 (g) + 2 H2O(g) 4 NH3(g) + 5 O (g) ---------> 4 NO(g) + 6 H2O(g)
Compound ∆Hf (kJ/mole) ∆S (J/mole K) C2H4 52.4 219.3 C2H6 –84.68 229.2 SiO2 –910.7 41.5 HF –273.3 173.8 SiF4 –1615.0 282.8 NH3 –45.9 192.9 O2 1.88 2.43 NO 91.3 210.8 H2O(g) –241.8 188.8 4 NH3 + 5 O2 -> 4 NO + 6 H2O
You will not find “hydroxide” in the stockroom, but you will find sodium hydroxide (NaOH) andpotassium hydroxide (KOH). Lithium hydroxide (LiOH) is expensive and used in spacecraft airfilters since hydroxide reacts with carbon dioxide, and lithium is lighter than sodium or potassium.Cesium and francium hydroxides are very expensive and little used. Is this information consistentwith your answer to the previous question?
Calculate ΔH° for the reaction using the given bond dissociation energies. CH4(g)+2O2(g)⟶CO2(g)+2H2O(g) Bond ΔH° (kJ/mol) O–OO–O 142 H–OH–O 459 C−HC−H 411 C=OC=O 799 O=OO=O 498 C–OC–O 358 What type of reaction is this?
Using the table of bond dissociation energies, the AH for the following reaction is CH4 + 20 2→ CO 2 + 2 H2O Bond D (kJ/mol) C-H 413 O=O 495 =0 799 463 -52 154 -1246 684 -808 kJ.
How do I do this?
Calculate AH for the reaction using the given bond dissociation energies. CH,(g)+2O,(g) — CO,(g) +2H,O(g) Bond AH (kJ/mol) 0-0 H-O C-H C=O 0=0 C-O AH° = 142 459 411 799 498 358 A kJ/mol This reaction is exothermic. endothermic.
parts b and c please
Hello, I need assistance with solving the following General Chemistry questions. Two in total, both attachments have been added.
Bonds Bond Energy (kJ/mol) C-H 411 C-Br 285 H-Br 362 Br-Br 190 Determine ΔH for the reaction: CH4 + 2Br2 ----> CH2Br2 + 2HBr
Using bond energies from the table, estimate ΔH for the reaction below. The OH group on the product side is attached to a carbon.CH2=CH2(g) + H2O(g) ↔ CH3CH2OH(g) Bond Energies, kJ/mol Single Bonds H C N O S F Cl Br I H 432 C 411 346 N 386 305 167 O 459 358 201 142 S 363 272 --- --- 286 F 565 485 283 190 284 155 Cl 428 327 313 218 255 249 240 Br 362 285 243 201 217 249 216 190 I 295 213 --- 201 --- 278 208 175 149 Multiple Bonds C=C 602 C=N 615 C=O 799 CºC 835 CºN 887 CºO 1072 N=N 418 N=O 607 S=O (in SO2) 532 NºN 942 O2 494 S=O (in SO3) 469
Which of the following statements is true? A Bond dissociation energies increase down a column of the periodic table B When ΔH° is positive, more energy is released in forming bonds than is needed to break bonds C When ΔH° is negative, more energy is needed to break bonds than is released in forming bonds D Bond dissociation energies decrease down a column of the periodic table

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