E (b.) (c.) A fictitious glass is consistent with data provided below. Table 1. Temperature (°C) 700 900 1100 Viscosity (P-poise) 1.09 x 10¹ Plot the data points from Table 1 in the figure above the table to show that it seems to "fit" the trends shown by the other glasses. Add an approximate trend line. 1.23 x 10 1.00 x 10 Viscosity (n) is the inverse of fluidity (p), where the latter obeys an Arrhenius formula: Therefore, viscosity obeys the following: p = A exp 1 exp(-27) RT n=no expl (Quiscous RT Determine the activation energy for viscous flow (Qviscous) for the fictitious glass. The glass-transition temperature is above the strain point, and this temperature is the lower limit of the supercooled liquid regime. The strain point in general is the temperature at which the viscosity equals 3 x 10¹4 P. What is the temperature of the strain point for our fictitious glass?

E (b.) (c.) A fictitious glass is consistent with data provided below. Table 1. Temperature (°C) 700 900 1100 Viscosity (P-poise) 1.09 x 10¹ Plot the data points from Table 1 in the figure above the table to show that it seems to "fit" the trends shown by the other glasses. Add an approximate trend line. 1.23 x 10 1.00 x 10 Viscosity (n) is the inverse of fluidity (p), where the latter obeys an Arrhenius formula: Therefore, viscosity obeys the following: p = A exp 1 exp(-27) RT n=no expl (Quiscous RT Determine the activation energy for viscous flow (Qviscous) for the fictitious glass. The glass-transition temperature is above the strain point, and this temperature is the lower limit of the supercooled liquid regime. The strain point in general is the temperature at which the viscosity equals 3 x 10¹4 P. What is the temperature of the strain point for our fictitious glass?

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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