dy = f(y). Sketch the graph of f(y) versus y, determine the critical (equilibrium) points, and classify each one as asymptotically stable or unstable. Draw the phase line, and sketch several graphs of solutions in the The following problem involves an equation of the form dt ty-plane. dy = y(y – 7)(y – 14), yo 2 0 dt The function y(t) = 0 is an unstable equilibrium solution. The function y(t) = 7 is an asymptotically stable equilibrium solution. The function y(t) = 14 is %3D an unstable equilibrium solution.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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Your answer is correct.
dy
dt f(y).
The following problem involves an equation of the form
Sketch the graph of f(y) versus y, determine the critical (equilibrium)
points, and classify each one as asymptotically stable or unstable.
Draw the phase line, and sketch several graphs of solutions in the
ty-plane.
dy
= v(y – 7)(y – 14), Yo > 0
dt
The function y(t) = 0 is
%3D
an unstable equilibrium solution. V
The function y(t) = 7 is
an asymptotically stable equilibrium solution.
The function y(t) = 14 is
an unstable equilibrium solution. ▼
Transcribed Image Text:Your answer is correct. dy dt f(y). The following problem involves an equation of the form Sketch the graph of f(y) versus y, determine the critical (equilibrium) points, and classify each one as asymptotically stable or unstable. Draw the phase line, and sketch several graphs of solutions in the ty-plane. dy = v(y – 7)(y – 14), Yo > 0 dt The function y(t) = 0 is %3D an unstable equilibrium solution. V The function y(t) = 7 is an asymptotically stable equilibrium solution. The function y(t) = 14 is an unstable equilibrium solution. ▼
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