dy = f(y). Sketch the graph of f(y) versus y, determine the critical (equilibrium) points, and classify each one as asymptotically stable or unstable. Draw the phase line, and sketch several graphs of solutions in the The following problem involves an equation of the form dt ty-plane. dy = y(y – 7)(y – 14), yo 2 0 dt The function y(t) = 0 is an unstable equilibrium solution. The function y(t) = 7 is an asymptotically stable equilibrium solution. The function y(t) = 14 is %3D an unstable equilibrium solution.
dy = f(y). Sketch the graph of f(y) versus y, determine the critical (equilibrium) points, and classify each one as asymptotically stable or unstable. Draw the phase line, and sketch several graphs of solutions in the The following problem involves an equation of the form dt ty-plane. dy = y(y – 7)(y – 14), yo 2 0 dt The function y(t) = 0 is an unstable equilibrium solution. The function y(t) = 7 is an asymptotically stable equilibrium solution. The function y(t) = 14 is %3D an unstable equilibrium solution.
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section: Chapter Questions
Problem 18T
Related questions
Question
![Your answer is correct.
dy
dt f(y).
The following problem involves an equation of the form
Sketch the graph of f(y) versus y, determine the critical (equilibrium)
points, and classify each one as asymptotically stable or unstable.
Draw the phase line, and sketch several graphs of solutions in the
ty-plane.
dy
= v(y – 7)(y – 14), Yo > 0
dt
The function y(t) = 0 is
%3D
an unstable equilibrium solution. V
The function y(t) = 7 is
an asymptotically stable equilibrium solution.
The function y(t) = 14 is
an unstable equilibrium solution. ▼](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5bf2309f-6e11-4f41-9b21-6b257a7c6b4a%2F74a61087-9fe9-4971-9499-2dd550d9f71b%2Fo53olg7_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Your answer is correct.
dy
dt f(y).
The following problem involves an equation of the form
Sketch the graph of f(y) versus y, determine the critical (equilibrium)
points, and classify each one as asymptotically stable or unstable.
Draw the phase line, and sketch several graphs of solutions in the
ty-plane.
dy
= v(y – 7)(y – 14), Yo > 0
dt
The function y(t) = 0 is
%3D
an unstable equilibrium solution. V
The function y(t) = 7 is
an asymptotically stable equilibrium solution.
The function y(t) = 14 is
an unstable equilibrium solution. ▼
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