The graph of F(y) vs y is as shown: ω 3 W = F(y) AW 2 4 y = -4 y = -3 y = -2 We are trying to find and match the equilibrium solutions of the autonom dy differential equation F(y). In the below, match to the right dt correspondence. y = 4 y = 6 -6 y =8 -4 6 = 8 Not a equilibrium point Not a equilibrium point Asymptotically Stable Semi Stable Not a equilibrium point Unstable

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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The graph of F(y) vs y is as shown:
y = -4
y = -3
y = -2
y = 4
y = 6
-6
y=8
-4
3-
W
We are trying to find and match the equilibrium solutions of the autonomous
differential equation d
dy
F(y). In the below, match to the right
dt
correspondence.
W=
1
2
F(y)
6
8 y
Not a equilibrium point
Not a equilibrium point
Asymptotically Stable
Semi Stable
Not a equilibrium point
Unstable
◄►
◄►
Transcribed Image Text:The graph of F(y) vs y is as shown: y = -4 y = -3 y = -2 y = 4 y = 6 -6 y=8 -4 3- W We are trying to find and match the equilibrium solutions of the autonomous differential equation d dy F(y). In the below, match to the right dt correspondence. W= 1 2 F(y) 6 8 y Not a equilibrium point Not a equilibrium point Asymptotically Stable Semi Stable Not a equilibrium point Unstable ◄► ◄►
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