If f is the function whose graph is shown in the figure below and g(x) = f(t) dt, find the values of g(0), g(1), g(2), g(3), g(4), and g(5). Then sketch a rough grapl 2. y= f(t) 1+ 1 4 Solution First, we notice that g(0) = f(t) dt = 0. From the figures below we see that g(1) is the area of a triangle. g(1) = f(t) dt = 1· 2) = To find g(2), we add to g(1) the area of a rectangle. g(2) = f(t) dt f(t) dt + f(t) dt = 1 + We estimate that the area under f from 2 to 3 is about 1.3, so

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Q: Use the given information to find f′(2). g(2) = 3 and g′(2) = −2 h(2) = −1 and h′(2) = 4

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Q: Use the given information to find f′(2). g(2) = 3 and g′(2) = −2 h(2) = −1 and h′(2) = 4

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