dX = (3nR) dT +( an- -)dv where R (= 0.08206 atm-L/mol-K or 8.314 J/mol-K) is the gas constant; van der Waals constant a = 3.84 atm-L2/mo²; n is the number of mole, V is the volume and I is the temperature. Determine the value of av (in units of atm) when n= 1 mol, V= 25.3 L and T=310 K (with 3 significant figures).

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Chapter1: Chemical Foundations
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### Transcription for Educational Website

#### Differential Equation:

\[ dX = (3nR) \, dT + \left(\frac{an^2}{V^2}\right) dV \]

#### Constants and Variables:
- \( R = 0.08206 \, \text{atm-L/mol-K or 8.314 J/mol-K} \) is the gas constant.
- \( a = 3.84 \, \text{atm-L}^2/\text{mol}^2 \) is the van der Waals constant.
- \( n \) is the number of moles.
- \( V \) is the volume.
- \( T \) is the temperature.

#### Problem Statement:
Determine the value of 

\[ \left( \frac{\partial X}{\partial V} \right)_T \]

(in units of atm) when \( n = 1 \, \text{mol} \), \( V = 25.3 \, \text{L} \), and \( T = 310 \, \text{K} \) (with 3 significant figures).

---

There are no graphs or diagrams to describe.
Transcribed Image Text:### Transcription for Educational Website #### Differential Equation: \[ dX = (3nR) \, dT + \left(\frac{an^2}{V^2}\right) dV \] #### Constants and Variables: - \( R = 0.08206 \, \text{atm-L/mol-K or 8.314 J/mol-K} \) is the gas constant. - \( a = 3.84 \, \text{atm-L}^2/\text{mol}^2 \) is the van der Waals constant. - \( n \) is the number of moles. - \( V \) is the volume. - \( T \) is the temperature. #### Problem Statement: Determine the value of \[ \left( \frac{\partial X}{\partial V} \right)_T \] (in units of atm) when \( n = 1 \, \text{mol} \), \( V = 25.3 \, \text{L} \), and \( T = 310 \, \text{K} \) (with 3 significant figures). --- There are no graphs or diagrams to describe.
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