drs - The semicircular rod has a 200 N load acting on it at the lower end in the direction shown in the figure. The rod is supported by a fixed support at A. Determine the internal axial force F, the shear force V and bending moment M at section C where the angle is 30°. 0.5 m 30 200 N

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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**Problem Statement:**

The semicircular rod has a 200 N load acting on it at the lower end in the direction shown in the figure. The rod is supported by a fixed support at A. Determine the internal axial force \( F \), the shear force \( V \), and bending moment \( M \) at section \( C \) where the angle is 30°.

**Diagram Explanation:**

The diagram shows a semicircular rod with a radius of 0.5 m. The rod is fixed at point \( A \) and has a load of 200 N applied at the bottom, at point \( S \). The load direction is vertically downward. Section \( C \) makes an angle of 30° with the vertical axis.

- **Points and Angles:**
  - \( A \): Fixed support.
  - \( B \): Top end of the semicircle.
  - \( C \): Point of interest where the angle is 30°.
  - \( S \): Point where the load is applied, directly below \( A \).
  - The semicircular rod makes a complete 180° turn from \( A \) to \( B \).

- **Forces:**
  - 200 N force is applied downward at \( S \).

**Tasks:**

Calculate the following at point \( C \):

1. **Internal Axial Force \( F \):** The component of force along the axis of the rod at section \( C \).
2. **Shear Force \( V \):** The force perpendicular to the rod's axis at section \( C \).
3. **Bending Moment \( M \):** The moment that causes bending at section \( C \).
Transcribed Image Text:**Problem Statement:** The semicircular rod has a 200 N load acting on it at the lower end in the direction shown in the figure. The rod is supported by a fixed support at A. Determine the internal axial force \( F \), the shear force \( V \), and bending moment \( M \) at section \( C \) where the angle is 30°. **Diagram Explanation:** The diagram shows a semicircular rod with a radius of 0.5 m. The rod is fixed at point \( A \) and has a load of 200 N applied at the bottom, at point \( S \). The load direction is vertically downward. Section \( C \) makes an angle of 30° with the vertical axis. - **Points and Angles:** - \( A \): Fixed support. - \( B \): Top end of the semicircle. - \( C \): Point of interest where the angle is 30°. - \( S \): Point where the load is applied, directly below \( A \). - The semicircular rod makes a complete 180° turn from \( A \) to \( B \). - **Forces:** - 200 N force is applied downward at \( S \). **Tasks:** Calculate the following at point \( C \): 1. **Internal Axial Force \( F \):** The component of force along the axis of the rod at section \( C \). 2. **Shear Force \( V \):** The force perpendicular to the rod's axis at section \( C \). 3. **Bending Moment \( M \):** The moment that causes bending at section \( C \).
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