Draw the structure with the molecular formula CgH140 that most likely produced the below IR and H NMR. The 13C NMR data is 78.3 ppm, 43.9 ppm, 27.3 ppm, 13.3 ppm. 100 80- 60 - 40- 20 1460 3400 2940 1370 1160 4000 3500 3000 2500 2000 1500 1000 500 Wavenumbers (cm-1)
Draw the structure with the molecular formula CgH140 that most likely produced the below IR and H NMR. The 13C NMR data is 78.3 ppm, 43.9 ppm, 27.3 ppm, 13.3 ppm. 100 80- 60 - 40- 20 1460 3400 2940 1370 1160 4000 3500 3000 2500 2000 1500 1000 500 Wavenumbers (cm-1)
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![Draw the structure with the molecular formula CgH140 that most likely produced the below IR and H NMR. The 13C NMR data is 78.3 ppm, 43.9
ppm, 27.3 ppm, 13.3 ppm.
100
80-
60 -
40-
20
1460
3400
2940
1370
1160
4000
3500
3000
2500
2000
1500
1000
500
Wavenumbers (cm-1)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5f4878da-2135-4f0d-8951-15d11473b219%2Fde1ca02d-02d8-43a3-953c-3871417dc6f3%2Fziedwl5n_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Draw the structure with the molecular formula CgH140 that most likely produced the below IR and H NMR. The 13C NMR data is 78.3 ppm, 43.9
ppm, 27.3 ppm, 13.3 ppm.
100
80-
60 -
40-
20
1460
3400
2940
1370
1160
4000
3500
3000
2500
2000
1500
1000
500
Wavenumbers (cm-1)
![8 20
1460
3400
2940
1370
1160
4000
3500
3000
2500
2000
1500
1000
500
Wavenumbers (cm-1)
singlet
6H
doublet
6H
broad
septet
1H
singlet
1H
8
6.
4
2
Chemical shift (ppm)
1st attempt
6 OF 25 QUESTIONS COMPLETED
の10](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5f4878da-2135-4f0d-8951-15d11473b219%2Fde1ca02d-02d8-43a3-953c-3871417dc6f3%2Foxdx1fg_processed.jpeg&w=3840&q=75)
Transcribed Image Text:8 20
1460
3400
2940
1370
1160
4000
3500
3000
2500
2000
1500
1000
500
Wavenumbers (cm-1)
singlet
6H
doublet
6H
broad
septet
1H
singlet
1H
8
6.
4
2
Chemical shift (ppm)
1st attempt
6 OF 25 QUESTIONS COMPLETED
の10
Expert Solution
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Step 1
Identification of organic compound can be done by spectroscopic techniques.
The techniques are : IR, 1H-NMR and 13C-NMR.
Chemical shift value of a proton/C depends on the electronic environment. Greater is the electron deficiency, higher will be the chemical shift value.
Splitting of a proton is based on the (n+1) rule where n is the no of chemically non-equivalent protons.
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