Draw the mechanism for the following reaction: H₂C- -C-CC-H Na* NH₂ H₂ H₂C-1₂2 Draw all missing reactants and/or products in the appropriate boxes by placing atoms on the canvas and connecting them with bonds. Add charges where needed. Electron-flow arrows should start on the H₂C-C-CE H₂ -Br -CH3
Reactive Intermediates
In chemistry, reactive intermediates are termed as short-lived, highly reactive atoms with high energy. They rapidly transform into stable particles during a chemical reaction. In specific cases, by means of matrix isolation and at low-temperature reactive intermediates can be isolated.
Hydride Shift
A hydride shift is a rearrangement of a hydrogen atom in a carbocation that occurs to make the molecule more stable. In organic chemistry, rearrangement of the carbocation is very easily seen. This rearrangement can be because of the movement of a carbocation to attain stability in the compound. Such structural reorganization movement is called a shift within molecules. After the shifting of carbocation over the different carbon then they form structural isomers of the previous existing molecule.
Vinylic Carbocation
A carbocation where the positive charge is on the alkene carbon is known as the vinyl carbocation or vinyl cation. The empirical formula for vinyl cation is C2H3+. In the vinyl carbocation, the positive charge is on the carbon atom with the double bond therefore it is sp hybridized. It is known to be a part of various reactions, for example, electrophilic addition of alkynes and solvolysis as well. It plays the role of a reactive intermediate in these reactions.
Cycloheptatrienyl Cation
It is an aromatic carbocation having a general formula, [C7 H7]+. It is also known as the aromatic tropylium ion. Its name is derived from the molecule tropine, which is a seven membered carbon atom ring. Cycloheptatriene or tropylidene was first synthesized from tropine.
Stability of Vinyl Carbocation
Carbocations are positively charged carbon atoms. It is also known as a carbonium ion.
![Draw the mechanism for the following reaction:
05
NN
H₂C-C-C=C-H
H₂
10+
[1]
Draw all missing reactants and/or products in the appropriate boxes by placing atoms on the canvas and
connecting them with bonds. Add charges where needed. Electron-flow arrows should start on the
electron(s) of an atom or a bond and should end on an atom, bond, or location where a new bond should be
created.
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H₂C-
Na* NH₂
H₂C- -C -Br
H₂
1
L
H EXP. CONT.
L
H₂
•C-C=C-H
H₂C-C-CE
H₂
NH₂
H₂C-
UI
-CH3
H₂C-
-Br:
-CH3](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3200e892-7b83-4670-8aa5-c4c84f2a6adb%2F62fbc4e3-af8a-42bf-8037-742070658ed1%2F2xwcimj_processed.jpeg&w=3840&q=75)
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