Given the following table of bond dissociation energies (in kcal/mol), what is AH° for this reaction? (CH3);С — Н + Br -Br (CH);С — Br + Н— Br CH3-H 105 (CH3)3C-H 91 CH3-Br 70 (CH3)зС-Br 65 Br-Br 46 H-Br 88 O +7 kcal/mol -7 kcal/mol O +16 kcal/mol O -16 kcal/mol O cannot be determined with this information
Given the following table of bond dissociation energies (in kcal/mol), what is AH° for this reaction? (CH3);С — Н + Br -Br (CH);С — Br + Н— Br CH3-H 105 (CH3)3C-H 91 CH3-Br 70 (CH3)зС-Br 65 Br-Br 46 H-Br 88 O +7 kcal/mol -7 kcal/mol O +16 kcal/mol O -16 kcal/mol O cannot be determined with this information
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
Related questions
Question
![**Bond Dissociation Energies and Reaction Enthalpy Calculation**
**Reaction:**
\[
(\text{CH}_3)_3\text{C-H} + \text{Br-Br} \rightarrow (\text{CH}_3)_3\text{C-Br} + \text{H-Br}
\]
**Bond Dissociation Energies (in kcal/mol):**
- \(\text{CH}_3-\text{H}\): 105
- \((\text{CH}_3)_3\text{C-H}\): 91
- \(\text{CH}_3-\text{Br}\): 70
- \((\text{CH}_3)_3\text{C-Br}\): 65
- \(\text{Br-Br}\): 46
- \(\text{H-Br}\): 88
**Question:**
What is \(\Delta H^\circ\) for this reaction?
**Choices:**
- \(+7\) kcal/mol
- \(-7\) kcal/mol
- \(+16\) kcal/mol
- \(-16\) kcal/mol
- cannot be determined with this information
**Explanation of Calculation:**
To calculate the standard enthalpy change (\(\Delta H^\circ\)) for the reaction, we use the bond dissociation energies:
\[
\Delta H^\circ = \text{(Sum of bond energies of reactants)} - \text{(Sum of bond energies of products)}
\]
1. **Reactants:**
- \((\text{CH}_3)_3\text{C-H}\): 91 kcal/mol
- \(\text{Br-Br}\): 46 kcal/mol
Total energy for breaking bonds = 91 + 46 = 137 kcal/mol
2. **Products:**
- \((\text{CH}_3)_3\text{C-Br}\): 65 kcal/mol
- \(\text{H-Br}\): 88 kcal/mol
Total energy for forming bonds = 65 + 88 = 153 kcal/mol
3. **Enthalpy Change:**
\[
\Delta H^\circ = 137 - 153 = -16 \text{ kcal/mol}
\]
Therefore, the correct choice is \(-16\) kcal/mol.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa6c5565a-787b-43d3-b23e-780453faf6da%2F11424fb3-b8ad-4b14-bb5f-1d3e641d8531%2Fhiypxkb_processed.png&w=3840&q=75)
Transcribed Image Text:**Bond Dissociation Energies and Reaction Enthalpy Calculation**
**Reaction:**
\[
(\text{CH}_3)_3\text{C-H} + \text{Br-Br} \rightarrow (\text{CH}_3)_3\text{C-Br} + \text{H-Br}
\]
**Bond Dissociation Energies (in kcal/mol):**
- \(\text{CH}_3-\text{H}\): 105
- \((\text{CH}_3)_3\text{C-H}\): 91
- \(\text{CH}_3-\text{Br}\): 70
- \((\text{CH}_3)_3\text{C-Br}\): 65
- \(\text{Br-Br}\): 46
- \(\text{H-Br}\): 88
**Question:**
What is \(\Delta H^\circ\) for this reaction?
**Choices:**
- \(+7\) kcal/mol
- \(-7\) kcal/mol
- \(+16\) kcal/mol
- \(-16\) kcal/mol
- cannot be determined with this information
**Explanation of Calculation:**
To calculate the standard enthalpy change (\(\Delta H^\circ\)) for the reaction, we use the bond dissociation energies:
\[
\Delta H^\circ = \text{(Sum of bond energies of reactants)} - \text{(Sum of bond energies of products)}
\]
1. **Reactants:**
- \((\text{CH}_3)_3\text{C-H}\): 91 kcal/mol
- \(\text{Br-Br}\): 46 kcal/mol
Total energy for breaking bonds = 91 + 46 = 137 kcal/mol
2. **Products:**
- \((\text{CH}_3)_3\text{C-Br}\): 65 kcal/mol
- \(\text{H-Br}\): 88 kcal/mol
Total energy for forming bonds = 65 + 88 = 153 kcal/mol
3. **Enthalpy Change:**
\[
\Delta H^\circ = 137 - 153 = -16 \text{ kcal/mol}
\]
Therefore, the correct choice is \(-16\) kcal/mol.
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 2 images
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Recommended textbooks for you
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
Organic Chemistry
Chemistry
ISBN:
9780078021558
Author:
Janice Gorzynski Smith Dr.
Publisher:
McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning
Elementary Principles of Chemical Processes, Bind…
Chemistry
ISBN:
9781118431221
Author:
Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:
WILEY