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Calculate the AH for the reaction: 4 NH3 (8) + 5O2 (4 NO(g) + 6 H₂O (g), from the following data: N₂ (g) + O₂ (g) N₂ (g) + 3H2 (g) 2 H₂ (g) + O2 (g) O +1994kJ O-1627 kJ O +1627 kJ O +755.4kJ O-1994 kJ O-755.4 kJ 2 NO (g) AH = - 180.5 kJ/mole 2 NH3 (g) AH = -91.8 kJ/mole 2 H₂O (g) AH = -483.6 kJ / mole

Calculate the AH for the reaction: 4 NH3 (8) + 5O2 (4 NO(g) + 6 H₂O (g), from the following data: N₂ (g) + O₂ (g) N₂ (g) + 3H2 (g) 2 H₂ (g) + O2 (g) O +1994kJ O-1627 kJ O +1627 kJ O +755.4kJ O-1994 kJ O-755.4 kJ 2 NO (g) AH = - 180.5 kJ/mole 2 NH3 (g) AH = -91.8 kJ/mole 2 H₂O (g) AH = -483.6 kJ / mole

Chemistry
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Calculate the AH for the reaction: 4 NH3 (8) + 5 O2(g) N₂ (g) + O₂ (g) N2 (g) + 3H2 (g) 2 H₂ (g) + O2 (g) O +1994kJ O-1627 kJ O +1627 kJ O +755.4kJ O-1994 kJ O-755.4 kJ 4 NO (g) + 6 H₂O (g), from the following data: 2 NO (g) AH = - 180.5 kJ/mole 2 NH3 (g) AH = 91.8 kJ/mole 2 H₂O (g) AH = - 483.6 kJ/mole
Transcribed Image Text:Calculate the AH for the reaction: 4 NH3 (8) + 5 O2(g) N₂ (g) + O₂ (g) N2 (g) + 3H2 (g) 2 H₂ (g) + O2 (g) O +1994kJ O-1627 kJ O +1627 kJ O +755.4kJ O-1994 kJ O-755.4 kJ 4 NO (g) + 6 H₂O (g), from the following data: 2 NO (g) AH = - 180.5 kJ/mole 2 NH3 (g) AH = 91.8 kJ/mole 2 H₂O (g) AH = - 483.6 kJ/mole
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