Draw the electron pushing mechanism
Q: What is the purpose of cyclic electron flow?
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A: Hi, thank you for your question. Since you have posted multiple questions, we will be answering the…
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Q: Draw the electron pushing mechanism
A: Electron pushing mechanism shows the jumping of electrons in the substrate and/or reaction…
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Q: Is it possible to have proton pumping in the absence of electron transport?
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Q: Which of the below electron carriers is actually carrying electrons? O NADH O FAD O ATP O NAD+
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A:
Q: Draw the electron pushing mechanism
A: Electron pushing mechanism shows the jumping of electrons in the substrate and reaction…
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Q: Draw electron flow during photosynthesis separately
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Q: Draw the electron pushing mechanism
A: Arrow pushing mechanism shows the jumping of electrons taking place within the substrate and/or…
Q: Draw the complete electron pushing mechanism that is enzyme catalyzed.
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Q: major electron sources for the electron transport pathway
A: In electron transport chain, NADH2 and FADH2 get reduced to give electrons.
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Q: How do electron transport reactions generate the protonmotive force?
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Q: explain in detail the electron transport chain in cellular respiration
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Q: What event is illustrated in the figure below? ATP ADP V
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Q: How does cyclic electron flow differ from noncyclic electron flow?
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Q: Describe the reaction between electrons, H+, and oxygen at thefinal step of electron transport.
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Draw the electron pushing mechanism
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- Refer to the figure below. Determine whether the given descriptions between the relationship of glucose and galactose is correct or incorrect. * сно ÇHO H OH HO-H H- -OH HO-H HO H- H-OH ČH,OH D-Glucose -H -OH H- -он CH,OH D-Galactose CORRECT INCORRECT Glucose and galactose are both Aldohexoses They constitute the structure of the disaccharide maltose They are epimers at carbon 4 They are not mirror images of each other, neither an enantiomeric pairAlthough the first two carbons of fructose and glucose are identical in structure to DHAP and GADP (from glycolysis), DHAP and GADP equilibriate on their in solution to favor the ketone over the aldehyde, while fructose and glucose do not. Why? a)The larger size of the molecule sterically hinders the isomerization b)The larger sugars have more OH groups which hydrogen bond and disrupt isomerization c)The larger sugars cyclize, and there is no carbonyl to isomerize in the cyclic form d)The larger sugars cyclize, and in the cyclic form the hydrogen bonding is very strong e)The larger sugars are less soluble in water than the smaller sugarsWhich of the following is/are reducing sugar/s?why? A CHOH CHOH CHOH OH OH CHOH OH CH,OH OH OH он C CHOH OH CHOH CHOH HỌ CH2OH OH OH OH OH ÓH u tte Select one: O a. Conly, it is a monosaccharide with a free carbonyl group O b. A and B only, both disaccharides are made from aldoses O C. B, C and D, they have at least one free carbonyl group O d. A and D only, both disaccharides are made from ketosis O. e. B and D, each has a free carboxyl group
- Amylose is comprised of glucose monomers connected by what kind of glycosidic bond? a (1 -->4) a (1 --> 6) b (1 --> 4) b (1 --> 6) None of the aboveWhich of the following statements is correct regarding the structures below? CHO CHO CHO -Н НО H НО н- ОН -Н - ОН CH2OH CAB All are structures of D-sugars. All are structures of ketohexoses. Only CAR is a monosaccharide. O Only CAP is a L-sugar. -ОН -ОН H-OH H-OH H- ОН CH₂OH CAR но-н H-OH н НО т н-он CH₂OH CAP CH₂OH Fo НО-Н H НО-Н H он CH₂OH CATConsider the disaccharide melibiose. Он снон -= H Он 5- -= д- H CH₂ H Он H H H ОН Н он Он Н Он melibiose What monosaccharides are formed when melibiose is hydrolyzed? Modify the structure of the disaccharide to identify the two monosaccharide products. CH₂OH он H H -= 5- H H CH2 H Он Н Н Он Н он Он Н Н Он
- Which of the following statements is TRUE for the enantiomer of the given monosaccharide? * ҫH,он H- -C-OH Но с -н H-C-OH ČH,OH It is an L-sugar that has opposite configuration around one carbon. It is a D-sugar that has opposite configuration around three carbons. O It is an L-sugar that has opposite configuration around three carbons. O It is a D-sugar that has opposite configuration around one carbon.Consider the disaccharide melibiose. сон ОН H Он Н Н Н CH2 H Он H Н Он -= 5. о H H он H Он melibiose What monosaccharides are formed when melibiose is hydrolyzed? Modify the structure of the disaccharide to identify the two monosaccharide products. CH₂OH OH H H он Н H CH2 H Он Н Н Он H Он он Н Н Он х Ш:Which of the following statements is correct regarding the structures below? CHO CHO H-OH ОН н ОН НО H НО -Н н- ОН CH₂OH CAB All are structures of D-sugars. All are structures of ketohexoses. Only CAR is a monosaccharide. 0 Only CAP is a L-sugar. Н I H CHO -ОН H-OH H-OH н- -ОН CH₂OH CAR H-OH -ОН НО-Н то н- H-OH CH₂OH CAP CH2OH to HO-H НО-н Н 1 - он CH₂OH CAT
- Which of the following best describes an L-glucose? The hydroxyl group attached to the penultimate carbon is located at the left side of the structure. The carbonyl group attached to the penultimate carbon is located at the right side of the structure. The carbonyl group attached to the penultimate carbon is located at the left side of the structure. The hydroxyl group attached to the penultimate carbon is located at the right side of the structure.In the structure in the picture, the monosaccharide units (alpha-D-galactopyranosyl and beta-D-allopyranose) are linked via alpha-1->3 glycosidic bond. Then, the formed disaccharide units are linked via beta-1->4 glycosidic bond. Then, an Oligosaccharide is formed which has 10 monosaccharide units, meaning that it contains 5 disaccharide units. Question: Is this oligosaccharide a good substrate for glycolysis? Provide two reasons for your answer.Consider the disaccharide maltose. Снон H H OH H Он Part 1 of 2 Сн, он Н H Н Н он H Он H Он H Он Classify the glycosidic linkage as a or ẞ. Select the single best answer. α Part: 1/2 Part 2 of 2 Modify the structure of maltose to show the monosaccharide products that form from hydrolysis. You may draw the structures in any arrangement that you like, so long as they aren't touching. H CH₂OH Н -= о Он H ОН снон Н H H Н OH Н он H OH H Он х