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- Complete the following paragraph regarding the structures below, then draw a relevant resonance contributor to support your selections in the paragraph. Your resonance contributor could be drawn to show either why one acid is stronger or why one acid is weaker. :0: .H B :0: A Compound [A/B] is the stronger acid because it is an electron [ withdrawing / donating ] group. By [increasing / decreasing ] the electron density on the ring, it will [ stabilize / destabilize] the conjugate base, and the [more / less ] stable the conjugate base, the [ stronger / weaker ] the acid. The resonance contributor below shows how electron density is [ withdrawn / donated ] to compound [A/B] showing it is the [ stronger / weaker ] acid resonance contributorDraw the major organic product of the Bronsted acid-base reaction. Include all lone pairs and charges as appropriate. Ignore any counterions. :0: NaOH H3. Use the inscribed polygon method to show the pattern of molecular orbitals of the following cyclononatetraenyl cation and anion. Explain their aromaticity. cyclononatetraenyl cation cyclononatetraenyl anion
- Draw a major resonance contributor of this enolate anion. Include all lone pairs in your structure. O CH2 O: Atoms, Bo and Ring Draw or tap aNeed help solving this, please show your work with the answer!This structure is considered to have 'anti-aromatic character'. Using the provided resonance structures, draw the curved electron-pushing arrows to show the interconversion between resonance hybrid contributors. Be sure to account for all bond-breaking and bond-making steps. :0: Select to Add Arrows :0: I I I I
- Why is compound I a stronger base than compound II? H H.: N. Because compound I is more stable than compound II. Because compound II is more sterically hindered. Because the lone pair on compound I is part of a delocalized pi-system. Because the lone pair on compound I is part of a delocalized pi-system.Complete the resonance structure of the keto form and add curved arrowsOrganic Chemistry Peter Vollhardt and Neil Schore Rank the compounds in order of decreasing reactivity towards electrophilic aromatic substitution. H3C- 0 COOH H3C- 0 Most reactive Least reactive Answer Bank -CH3 W.H. Freeman and Company presented by Macmillan Learning HOOC COOH
