**Finding the Net Force on an Object with Applied Forces****Problem Statement:**Two forces are applied to an object as shown in the diagram. Using \( F_1 = 27 \, \text{N} \), \( \phi_1 = 55^\circ \), \( F_2 = 31\, \text{N} \), and \( \phi_2 = 17^\circ \), find the net force on the object.**Diagram Explanation:**The diagram depicts a coordinate system with two forces \( F_1 \) and \( F_2 \) acting on an object at the origin. \( F_1 \) is directed at an angle \( \phi_1 = 55^\circ \) counterclockwise from the positive x-axis, and \( F_2 \) is directed at an angle \( \phi_2 = 17^\circ \) counterclockwise from the negative x-axis.**Questions:**2. **Magnitude:** - A. 18.22 N - B. 12.01 N - C. 31.43 N - D. 19.26 N - E. 21.03 N - F. 30.75 N3. **Direction (counter-clockwise from +x axis):** - A. 148.5° - B. 175.2° - C. 236.2° - D. 142.3° - E. 137.3° - F. 250.7°**Review Strategy:**To find the resultant force:1. Use vector components to break down \( F_1 \) and \( F_2 \) into \( x \) and \( y \) components.2. Sum the components in each direction to get the resultant vector.3. Calculate the magnitude of the resultant vector using \( \sqrt{R_x^2 + R_y^2} \).4. Determine the direction of the resultant vector using \( \tan^{-1}(R_y/R_x) \).By following these steps, students can effectively find both the magnitude and direction of the net force.

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Download sics_practi....docx ?dl=0&preview=(B)+Unit_GWs+and+Test_(carpet).pdf Two forces are applied to an object as shown. Using F₁ = 27_N, 1₁ = 55°, F₂ = 31_N, and 2 = 17°m, find the net force on the object. F₁ 2 F2 2. magnitude A. 18.22_N D. 19.26 N 21.03 N B. 12.01 N E. C. 31.43 N F. 30.75_N 1--1 direction (counter-clockwise from +x axis) D. 142.3° A. 148.5° E. 137.3° B. 175.2° F. 250.7° C. 236.2° 1--1 physics_practi....docx MacBook Pro 3. 91 Sign in Sign up ⠀ Ⓡ | 0 E Show All

Download sics_practi....docx ?dl=0&preview=(B)+Unit_GWs+and+Test_(carpet).pdf Two forces are applied to an object as shown. Using F₁ = 27_N, 1₁ = 55°, F₂ = 31_N, and 2 = 17°m, find the net force on the object. F₁ 2 F2 2. magnitude A. 18.22_N D. 19.26 N 21.03 N B. 12.01 N E. C. 31.43 N F. 30.75_N 1--1 direction (counter-clockwise from +x axis) D. 142.3° A. 148.5° E. 137.3° B. 175.2° F. 250.7° C. 236.2° 1--1 physics_practi....docx MacBook Pro 3. 91 Sign in Sign up ⠀ Ⓡ | 0 E Show All

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter26: Electric Potential

Section: Chapter Questions

Problem 2PQ: Review Return to Chapter 8 and the potential energy associated with both gravity near the surface of...

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Concept explainers

Units and Dimensions

These are generally defined as the terms which precede or describes the dimensions further. These are also further divided into two parts namely fundamental units and the derived units.

Question

**Finding the Net Force on an Object with Applied Forces**

**Problem Statement:**
Two forces are applied to an object as shown in the diagram. Using \( F_1 = 27 \, \text{N} \), \( \phi_1 = 55^\circ \), \( F_2 = 31\, \text{N} \), and \( \phi_2 = 17^\circ \), find the net force on the object.

**Diagram Explanation:**
The diagram depicts a coordinate system with two forces \( F_1 \) and \( F_2 \) acting on an object at the origin. \( F_1 \) is directed at an angle \( \phi_1 = 55^\circ \) counterclockwise from the positive x-axis, and \( F_2 \) is directed at an angle \( \phi_2 = 17^\circ \) counterclockwise from the negative x-axis.

**Questions:**

2. **Magnitude:**
- A. 18.22 N
- B. 12.01 N
- C. 31.43 N
- D. 19.26 N
- E. 21.03 N
- F. 30.75 N

3. **Direction (counter-clockwise from +x axis):**
- A. 148.5°
- B. 175.2°
- C. 236.2°
- D. 142.3°
- E. 137.3°
- F. 250.7°

**Review Strategy:**
To find the resultant force:
1. Use vector components to break down \( F_1 \) and \( F_2 \) into \( x \) and \( y \) components.
2. Sum the components in each direction to get the resultant vector.
3. Calculate the magnitude of the resultant vector using \( \sqrt{R_x^2 + R_y^2} \).
4. Determine the direction of the resultant vector using \( \tan^{-1}(R_y/R_x) \).

By following these steps, students can effectively find both the magnitude and direction of the net force.

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