Do these data provide convincing evidence that the means for the numbers of pretzels consumed are not the same for all four treatments? Test the relevant hypotheses using a significance level of 0.05.Calculate the test statistic. (Round your answer to two decimal places.)F =Use technology to find the P-value. (Round your answer to four decimal places.)P-value =What can you conclude?O Reject H.. The data provide convincing evidence that the mean number of pretzels consumed is not the same for all four treatments.O Reject Hn. The data do not provide convincing evidence that the mean numberpretzels consumed is not the same for all four treatments.O Fail to reject Hn: The data provide convincing evidence that the mean number of pretzels consumed is not the same for all four treatments.O Fail to reject H. The data do not provide convincing evidence that the mean number of pretzels consumed is not the same for all four treatments. A research paper describes an experiment in which 74 men were assigned at random to one of four treatments.1. viewed slides of fit, muscular men2. viewed slides of fit, muscular men accompanied by diet and fitness-related text3. viewed slides of fit, muscular men accompanied by text not related to diet and fitness4. did not view any slidesThe participants then went to a room to complete a questionnaire. In this room, bowls of pretzels were set out on the tables. A research assistant noted how many pretzels were consumed by each participant while completing the questionnaire. Data consistent with summary quantities given in the paper are given in the followingtable.Treatment 1Treatment 2Treatment 3Treatment 4751314314.213126345355313233210771111510710

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Answered: Do these data provide convincing…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Test the claim that the proportion of people who own cats is larger than 60% at the 0.05 significance level. The null and alternative hypothesis would be: Ho:p ≤ 0.6 Ho:p> 0.6 Ho:p> 0.6 Ho: 0.6 H₁ p 0.6 Hp 0.6 H₁0.6 O The test is: right-tailed left-tailed two-tailed O Based on a sample of 700 people, 61% owned cats The test statistic is: The p-value is: Based on this we: O Fail to reject the null hypothesis O Reject the null hypothesis (to 2 decimals) (to 4 decimals)
true or false If the p-value is 0.13 and the level of significance , αα , is 0.05 in a hypothesis test for a mean, then we accept the null hypothesis.
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← N 6 F2 ew an example Get more help. X 3 The display provided from technology available below results from using data for a smartphone carrier's data speeds at airports to test the claim that they are from a population having a mean less than 5.00 Mbps. Conduct the hypothesis test using these results. Use a 0.05 significance level. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. Click the icon to view the display from technology. Assuming all conditions for conducting a hypothesis test are met, what are the null and alternative hypotheses? OA. Ho: 5.00 Mbps 8 M DII FB 1 K Print ( 9 H T-Test H<5.00 t= -0.288047 p=0.387332 x=4.78 Sx=5.123487 n=45 < I 6 F9 O L command Done ) O F10 P : ; I option F11 { [ ? 1 + = 11 - X I Check answer F12 } ] delete return shift
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Q: Using the data (provided below this question) test the hypotheses that the mean difference in writing and reading scores is zero and that the mean difference in math and science scores is zero. Use the paired-sample procedure. Use a 5% significance level if the problem doesn’t give an alpha. Note: Please only provide the t stat, p(T<=t) value and critical value. No need to explain the steps. School District Writing Reading Math Citizenship Science All Indian Hill 95 98 89 95 91 83 Wyoming 98 96 86 93 87 81 Mason City 96 92 85 94 86 72 Madiera 94 95 88 82 88 69 Mariemont 99 92 74 89 88 68 Sycamore 85 88 80 87 84 68 Forest Hills 93 91 73 85 88 67 Kings Local 92 86 78 82 78 64 Lakota 90 88 73 85 81 64 Loveland 85 93 72 86 86 61 Southwest 92 82 73 78 73 58 Fairf ield 90 86 71 83 77 57 Oak Hills 88 86 75 77 79 57 Three Rivers 87 85 66 84 77 56 Milford 82 86 72 82 76 53 Ross 84 85 66 75 78 52 West Clermont 88 83 63 73 70 48 Reading 88 80 58 76 75…
Test the claim that the proportion of men who own cats is significantly different than the proportion of women who own cats at the 0.02 significance level. The null and alternative hypothesis would be: Ho: M = μF Ho: PM = PF H₁ μM μF H₁:PM > PF The test is: left-tailed right-tailed two-tailed Based on a sample of 60 men, 30% owned cats Based on a sample of 40 women, 45% owned cats The test statistic is: Ho: PM = PF H₁: PM μF (to 2 decimals) (to 2 decimals) Ho: PM = PF Ho: M = μF H₁:PM ‡ PF H₁: μM < MF
You are conducting a study to see if the probability of catching the flu this year is significantly more than 0.61. You use a significance level of a = 0.005. Ho:p = 0.61 H1:p > 0.61 You obtain a sample of size n = 572 in which there are 371 successes. What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value = The p-value is. less than (or equal to) a greater than a This test statistic leads to a decision to.. reject the null accept the null fail to reject the null As such, the final conclusion is that... There is sufficient evidence to warrant rejection of the claim that the probability of catching the flu this year is more than 0.61. There is not sufficient evidence to warrant rejection of the claim that the probability of catching the flu this year is more than 0.61. O The sample data support the claim that the probability of catching…
You are conducting a study to see if the proportion of women over 40 who regularly have mammograms is significantly different from 0.84. You use a significance level of a = 0.02. Ho:p = 0.84 Ha:p +0.84 You obtain a sample of size n = 700 in which there are 574 successes. What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value = The p-value is... O less than (or equal to) a O greater than a This test statistic leads to a decision to... O Reject the null O Accept the null O Do not reject the null As such, the final conclusion is that... O There is sufficient evidence to warrant rejection of the claim that the proportion of women over 40 who regularly have mammograms is different from 0.84. O There is not sufficient evidence to warrant rejection of the claim that the proportion of women over 40 who regularly have mammograms is different from…
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