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- A t distribution with 8 degrees of freedom is graphed below. The region under the curve to the right of t=0.5 is shaded. 0.4- 0.3+ 0.2+ 0.1 + t = 0.5 Find the area of the shaded region. Round your answer to three decimal places. X ŚA Assume that a randomly selected subject is given a bone density test. Those test scores are normally distributed with a mean of 0 and a standard deviation of 1. Draw a graph and find the probability of a bone density test score greater than 0.81. 2 Sketch the region. Choose the correct graph below. OA. iew an example Get more help. F2 W S X H and ANAN 0.81 5373255.docx # 3 80 E D Q C $ 4 R F % OB. NO REF SAMPLE....pdf 5 V T -0.81 0.81 G 6 B A MacBook Air F6 Y H TEMPLATE Sel...docx & 7 N F7 OC.. U * 8 J A DII FB I M 0.81 D ( 9 Q K G resume..docx DD O ^ -0.81 Clear all : ; I { [ + option = 11 I ? 1 Check answer I Show All F12 } 1 X deleteA t distribution with 3 degrees of freedom is graphed below. The region under the curve to the right of t0.945 is shaded. The area of this region is 0.945 . 0.1 0.2 0.3 0.4 =Area0.945 t0.945 Find the value of t0.945 . Round your answer to three decimal places.
- R tab Decide which of the following statements are true. Answer esc 1 ! 1 alt 9 a Z ok x360 hp from any angle. @ 2 W S → There are a limited number of normal distributions. The Inflection points for any normal distribution are one standard deviation on either side of the mean. The x-axis Is a horizontal asymptote for all normal distributions. The line of symmetry for all normal distributions is x = 0. X # 3 e d C $ 4 C r 20 - % 5 M g hp cy n 7 U D N 8 9 WAYAN m O ) 0 4 P - > Tables Keyboard Shor Submit Answer O { [ ctrl Oct 4 ? 11 8P(X a) = 0.1 [Choose ] [Choose ] a = 7.44 a = 12.56 6.71To find Class Intervals when step-deviations, X and Assumed Mean given Find class interval if mean of the following distribution is 33 and assumed mean is 35. Step deviation: Frequency: -3 -2 -1 +1 +2 10 25 30 20 10
- percent over 250 lbs: 6.01 What percent of the N(161.59, 48.96) distribution is above 250? (Enter your answer rounded to two decimal places.) percent above 250: (c) Based on your answers in parts (@) and (b). do you think it is a good idea to summarize the distribution of weights by an N(161 59 48 96).distribution? Publisher: W.H. Free Question Source: Moore, The Basic Practice Of Statistics, &e tems of use contac Us help about us cafeers 4:16 PM 10/2/2020 | 耳 a %23 3) hp prt sc $12 insert 19 144 17A t distribution with 6 degrees of freedom is graphed below. The region under the curve to the right of t0.04 is shaded. The area of this region is 0.04. 10.04= 0.4- x 0.3 Area = 0.04 I ¹0.04 Find the value of 0.04. Round your answer to three decimal places. 0.2+ 0.1+3 decimal placessGiven a normal distribution with μ = 35 and σ = 8, finda.the normal curve area to the left of x = 22 b.the value of x that has 80% of the normal curve area to the left c.the two values of x that contain the middle 75% of the normal curve area. d.the normal curve area between x = 32 and x = 41
- Using the normal distribution table find Z0 such that: P(-ZosZs Zo) = .994 2.75 1.54 2.11 2.18K Use the central limit theorem to find the mean and standard error of the mean of the indicated sampling distribution. Then sketch a graph of the sampling distribution. The per capita consumption of red meat by people in a country in a recent year was normally distributed, with a mean of 114 pounds and a standard deviation of 38.8 pounds. Random samples of size 18 are drawn from this population and the mean of each sample is determined. View an example Get more help. G Clear all Check answerALler Find the indicated z score. The graph depicts the standard normal distribution with mean 0 and standard devlation 1. Shaded area is 0.8012. -3 -2 -1 0. 1 2 O(-1.17, 1.42) 0(-1.88, 0.84) o(-0.84, 1.88) 0(-1.42, 1.17) Continue 2021 McGraw-Hill Education. All F SAMSUNG
