Find the z-score for which 89% of the distribution's area lies between -z and z.-1.5982, 1.5982-2.7653, 2.7653-2.8438, 2.8438-1.3459, 1.3459

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Answered: Find the z-score for which 89% of the…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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The pie chart shows the distribution of the opinions of parents on whether a college education is worth the expense. An economist claims that the distribution of the opinions of teenagers is different from the distribution for parents. To test this claim, you randomly select 197 teenagers and ask each whether a college education is worth the expense. Strongly agree The table to the right shows the results. At a = 0.05, test the economist's claim. Click the icon for the pie chart of the distribution. Response Somewhat agree Neither agree nor disagree Somewhat disagree Strongly disagree Survey results State Ho and H₂ and identify the claim. Ho: The distribution of the opinions of whether a college education is worth the expense is the same for teenagers and parents. Ha: The distribution of the opinions of whether a college education is worth the expense is different for teenagers and parents. Which hypothesis is the claim? Ho На Calculate the test statistic. 2 x = (Round to three decimal…
The data table shows the ages in years of 10 men with systolic blood pressure. The Age,x: 18, 24, 39, 45, 49, 63, 71, 29, 57, 22 and systolic blood pressure, y: 109, 121, 142, 133, 199, 186, 199, 132, 177, 117. The sample correlation coefficient r is 0.913. Remove the data entry for the man who is 49 years old and has a systolic blood pressure of 199 millimeters of mercury from the data set and find the new correlation coefficient.
how did you find the Z score?
A survey recently went out to 15 university presidents across a certain country. The data represents the ages of the different presidents. Use a stem-and-leaf plot that has two rows for each stem to represent their ages. 53, 62, 57, 53, 58, 55, 61, 67, 57, 62, 50, 61, 59, 52, 74 O Stems Leaves Determine the leaves in the stem-and-leaf plot shown at the right. 5 (Use ascending order.) 6. 6. 7 Which of the following best summarizes what the stem-and-leaf plot tells you about the data? A. The plot shows that there is an equal amount of university presidents under the age of 60 as there is above the age of 60. B. The plot shows that most university presidents have ages that range from 65 to 75 years old. O C. The plot shows that the age of the university presidents cluster around age 60. O D. The plot shows that most university presidents have ages that range from 50 to 65 years old. ? Click to select your answer(s).
Find the z-score that has 68.4% of the distribution's area to its right. Can you also give the steps in the calculator? TI-84
A large automobile insurance company selected samples of single and married male policyholders and recorded the number who made an insurance claim over the preceding three-year period. Z-value p-value Single Policyholders n₁ = 440 Number making claims = 88 a. Use a = 0.05. Test to determine whether the claim rates differ between single and married male policyholders. (to 2 decimals) (to 4 decimals) X Married Policyholders n2 = 840 Number making claims 126 We can conclude ✔ that there is the difference between claim rates. b. Provide a 95% confidence interval (to 4 decimals) for the difference between the proportions for the two populations. Enter negative answer as negative number. X * )
For the residents in 2014, use R to calculate the interval with 99% certainty that the interval contains the actual population mean of the residents by census tracts. Type in the interval with keyboard. We also know that in each year, the number of residents by census tract in the State of Maryland follows a normal distribution, and the variance in the number of residents within the State of Maryland is the same for different years. POP2014: 3072, 1989, 3794, 2689, 3211, 3722, 4385, 4009, 7598, 3862, 3097, 2726, 4881, 4157, 2570, 2512, 2518, 4863, 4147, 7139, 6067, 6819, 3705, 3239, 3824, 4977, 2576, 2940, 9791, 5231, 5634, 5337, 4205, 3888, 5562, 3335, 3770, 1808, 2045, 1532, 5420, 4993, 6109, 4377, 5424, 4976, 4507, 3738, 2827, 3485, 1559, 5199, 4702, 3971, 3803, 3356, 4670, 3816, 5477, 4760, 3126, 3630, 3755, 3795, 2578, 3382, 4005, 2442, 6096, 3799, 3843, 3836, 6046, 6431, 3561, 3142, 4829, 5058, 2471, 6119, 3523, 3094, 3146, 3356, 2618, 2366, 4266, 4016, 6080, 1554, 6878, 3645,…
The IQR represents the spread of the middle 50% of the data. Do you think the IQR in this problem is large or small? Here is the data. 0, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3, 3, 3, 3, 4, 4, 4, 4, 4, 5, 5, 6, 7, 13, 14 Median is 3. Min # is 0 Max # is 14 Q1 is 2 Q2 is 3 Q3 is 4 IQR=Q3 (4)-Q1(2) IQR=2
Which z-score has the higher frequency? (a) z = +1.0 or z = +2.3; (b) z = −2.8 or z = −1.7; (c) z = −.70 or z = −.20; (d) z = 0.0 or z = −2.0.
How would I identify the p-value?

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Find the z-score for which 89% of the distribution's area lies between -z and z. -1.5982, 1.5982 -2.7653, 2.7653 -2.8438, 2.8438 -1.3459, 1.3459