The value given below is discrete. Use the continuity correction and describe the region of the normal distribution that corresponds to the indicated probability. Probability of exactly 5 passengers who do not show up for a flight Choose the correct answer below. OA. The area to the left of 4.5 OB. The area to the right of 5.5 OC. The area between 4.5 and 5.5 OD. The area to the left of 5.5 OE. The area to the right of 4.5 B

Q: Find t0.95t0.95 for TT distribution with 2020 degrees of freedom. t0.95=t0.95= (Round the answer to…

A: The given degrees of freedom is 20 and area is 0.95.

Q: Use the standard normal table to find the​ z-score that corresponds to the cumulative area 0.0624.…

A: Given information- We have given the standard normal distribution table. We have to find the z-score…

Q: 1. z = 0.44 Z = -0.84 Z = 1.28 2.

A:

Q: Q Find the area of the shaded region. The graph depicts the standard normal distribution with mean 0…

A:

Q: Sketch a standard normal curve and shade the area that lies to the left of a. 2.19, b. - 1.63, c. 0,…

A: Hi! Thank you for the question, As per the honor code, we are allowed to answer three sub-parts at a…

Q: Assume that a randomly selected subject is given a bone density test. Bone density test scores are…

A: Obtain the 2th percentile of the distribution. The 2thpercentile of the distribution is obtained…

Q: Assume that a randomly selected subject is given a bone density test. Those test scores are normally…

A: the PDF of normal distribution is = 1/σ * √2π * e ^ -(x-u)^2/ 2σ^2standard normal distribution is a…

Q: Find the margin of error for the given values of c, s, and n. c= 0.90, s = 4, n= 26 Click the icon…

A: Givens=4n=26c=0.90

Q: Find the margin of error for the given values of c, s, and n. c = 0.98, s = 2.3, n = 18 Click the…

A: Confidence level(c)=0.98standard deviation(s)=2.3sample size(n)=18

Q: 2 Find x0.99 for x² distribution with 40 degrees of freedom. X 2 X0.99

A: It is needed to find the value of  for 40 degrees of freedom.

Q: Assume that a randomly selected subject is given a bone density test. Those test scores are normally…

A: From the provided information, Mean (µ) = 0 Standard deviation (σ) = 1 Let X be a random variable…

Q: Find the area of the shaded region. The graph to the right depicts IQ scores of adults, and those…

A:

Q: Find f0.01f0.01 for FF distribution with (55,77) degrees of freedom. f0.01

A: The given degrees of freedom is (55, 77).

Q: The middle .975 area of the z distribution is between what 2 numbers?

A: Given that,z distribution is used.Area = 0.975

Q: Write the binomial probability and the normal probability for the shaded region of the graph. Find…

A:

Q: Find the margin of error for the given values of c, s, and n. c = 0.99, s 5, n=9 E Click the icon to…

A: we have given that  c= 0.99 ,s=5 ,n=9

Q: Find the z-score that is greater than the mean and for which 70% of the distribution's area lies to…

A: Solution : It is given that z-score should be greater than the mean, the z-score should be positive…

Q: Find the z-score for which 99% of the distribution's area lies between -z and z. Click to view page…

A: The objective is to find the z-score for 99% of the distributions area lie between –z and z.   That…

Q: The value given below is discrete. Use the continuity correction and describe the region of the…

A: The continuity correction suggests adding or subtracting 0.5 from discrete values to get an accurate…

Q: ASsume that a randomly selected subject is given a bone density test. Those test scores are normally…

A: We have to find  correct answer of graph and probability...

Q: Assume that a randomly selected subject is given a bone density test. Those test scores are normally…

A: For the given problem, we need to find the probability that a given score is between -2.08 and 3.73…

Q: Assume the readings on thermometers are normally distributed with a mean of 0°C and a standard…

A: The given information is that the readings on thermometers are distributed normally with mean 0 and…

Q: You randomly select and weigh 12 samples of an allergy medicine. Assume the weights are normally…

A: Given that n =12, t0.99 = ?

Q: Sketch a standard normal curve and shade the area that lies to the left of a. 2.15, b. - 1.61, c. 0,…

A: One of the most significant probability distributions for a continuous random variable is the normal…

Q: Decide whether the random variable x is discrete or continuous. Explain your reasoning. Let x…

A: Here temperature of thermometer of a person can not count because random variables in the…

Q: Assume that a randomly selected subject is given a bone density test. Those test scores are normally…

A: Z score = -0.51( Left tailed )

Q: The value given below is discrete. Use the continuity correction and describe the region of the…

A: Continuity Correction Factor : The value 0.5 subtracted or added depending on the problem to a…

Q: Find the area of the shaded region. The graph to the right depicts IQ scores of​ adults, and those…

A: GivenMean(μ)=100standard deviation(σ)=15

Q: Assume that a randomly selected subject is given a bone density test. Those test scores are normally…

A:

Q: Find the margin of error for the given values of c, s, and n. c= 0.99, s = 6, n = 13 Click the icon…

A: Given,c=0.99s=6n=13degrees of freedom(df)=n-1df=13-1=12α=1-0.99=0.01α2=0.005t0.005(12)=3.055   (from…

Q: Directions: True or False, In the answer sheet, write the word TRUE if the statement is correct and…

A: (a) Statement : The total area of the normal curve is 1. Answer : True  Explanation  :  The total…

Q: Assume that a randomly selected subject is given a bone density test. Those test scores are normally…

A:

Q: Please answer d, e, f

A: The degrees of freedom, df = n – 1 = 16 – 1 = 15d. To the right of 2.583,The p-value is obtained…

Q: Assume that a randomly selected subject is given a bone density test. Those test scores are normally…

A: Z has follows standard normal distribution with mean 0 and standard deviation 1.

Q: Assume that a randomly selected subject is given a bone density test. Those test scores are normally…

A: From the provided information, Mean (µ) = 0 Standard deviation (σ) = 1 X~N (0, 1) Here X be a random…

Q: Find the z-scores for which 80% of the distribution's area lies between -z and z. Click to view page…

A: From the provided information,80% of the distribution's area lies between -z and z.