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- Ill.siven the following pedigree below, use Punnett squares for each of the following possibilities: a) X- linked dominant, b) X-linked recessive, c) Autosomal dominant and d) Autosomal recessive in order to determine what is the mode of transmission of this trait. Disease allele = Xª, x², A or a depending on mode of transmission of the disease respectively. Unaffected X chromosome = X *Homozygous unaffected/No 1 *2 carrier=Normal II 1 *4 1 2 3 6. 7 8 a) X-linked dominant 11x12 b) X-linked recessive I 1 x1 2 c) Autosomal dominant 11x12 d) Autosomal recessive I1x12 IV. Based on your analysis what is the mode of transmission for this disease? O+Figure 3 shows the karyotypes of two individuals suffering from a genetic disorder. a) Name the genetic disorder for individuals A and B. b) Give three characteristics of individual B. c) What is the gender of individual A?Ensure answers are clearly labelled a) & b). a) Consider the following pedigree. The solid symbols represent affected individuals. Which of the following is / are possible genotypes for IV-2 with respect to this disease? Please type 1 - 4, and indicate yes or no only for each I II III 1 IV 3 V 1 1. ХАха 2. хаха 3. Aa 4. A1Α2 b) Genes A, B and C are on the same chromosome linked in cis (coupling) conformation. A is 23 cM from B, and B is 17 cM from C. The distance between A and C is 40 cM. The coefficient of coincidence is 0.75 for a trihybrid test cross. How many individuals with the genotype aaBbcc do you expect to see among the offspring of the cross if 1000 offspring are obtained? Please show your calculations and round your answer off to the nearest whole number.
- Now assume that the pedigree shown in question 1 shows the inheritance of a rare genetic disease. a) The disease is most likely autosomal dominant b) The disease is most likely autosomal recessive c) The disease is equally likely to be either autosomal dominant or autosomal recessive, but cannot be x-linked d) Cannot be determined from the information givenuestion 3 (1 point) Suppose that a grandfather, mother, and son all have the same homozygous dominant genotype for a gene that controls facial hair growth. The grandfather and son have thick beards, but the mother has no significant facial hair. What type of hon-Mendelian inheritance is this? O a) Sex-influenced inheritance O b) Sex-limited inheritance OC) Onset of genetic expression D d) X-linked dominant inheritanceQ1: Choose the correct answer of the following questions 1) Which can a chromosome map show? A) the sex of the individual B) the position of genes on a chromosome C) the presence of mutant alleles D) whether a gene is autosomal or recessive
- In domesticated cats, the following are Independently assorting: 6. Normal ears (T) is dominant to tufted ears (t); Curved whiskers (C) is dominant to straight whiskers (c); The presence of six toes (S) is dominant to five toes (s); Gene for hair length is an X-linked codominant. The three phenotypes for hair length are long (XHXH), medium (X"X*), and short (X"Xh); medium is the heterozygous condition. Given two parents: TtccSSXHXh x TtCcSsXHY a) How many different gametes could be formed in the female cat with respect to these four traits? b) How many different phenotypes are possible in the offspring from this mating?If a Mother's genotype is IAi and her Daughter's genotype is ii and the mother claims a man who is type B as the father... a) Is that possible? Explain. b) The accused man can prove that both of his parents are type AB. Is it possible for him to be type B? If so, what is his genotype? Explain. d) Does the answer in part c change the answer in part b? Explain.Hemophilia is an X-linked recessive phenotype. Suppose a man who expresses the hemophilia phenotype has children with a woman who has the normal phenotype (and does not have a family history of hemophilia). If the couple have a son, what are the chances that he will have hemophilia? A) 50% B) 25% C) 0% D) 100%
- Question:- A) Give one domain.motif found in the SRY portion and state clearly how it leads to the development of the Wollfian system. B) Explain the genotype and the phenotype of an XY female and how such an individual could occur. C) Explain the genotype and the phenotype of an XX male and how such an individual could occur.Consider a couple: a woman who is homozygous for a recessive mutation that causes X-linked colorblindness, and a man with full color vision (he does not carry a copy of the mutation). a) What is the probability that a son of this couple will be colorblind? b) What is the probability that a daughter of the couple will be colorblind?The Xg cell-surface antigen is coded for by a gene located on the X chromosome. No equivalent gene exists on the Y chromosome. Two codominant alleles of this gene have been identified: Xg1 and Xg2. A woman of genotype Xg2/Xg2 bears children with a man of genotype Xg1/Y, and they produce a son with Klinefelter syndrome of genotype Xg1/Xg2Y. Using proper genetic terminology, briefly explain how this individual was generated. In which parent and in which meiotic division did the mistake occur?