I don't really understand what is going on here or the equations to do this help. Displacement CurrentA parallel plate capacitor with circular plates of radius R = 16 cm and plate separation d = 6 mm is being charged at the rate of 9 C/s.R00DisplacementCurrentWhat is the displacement current through a circular loop of radius r = 9 cm centered on the axis of the capacitor?current=DisplacementCurrentOutWhat is the displacement current through a circular loop of radius r = 21 cm centered on the axis of the capacitor (note that this radius is bigger than the radius of the capacitor)?current=MagneticFieldWhat is the magnitude of the magnetic field between the capacitor plates at a radius r = 9 cm from the axis of the capacitor?B=

Given: In this question, the given details are, A parallel plate capacitor with circular plates of radius, R=16.0 cm and plate separation, d=6 mm is being charged at the rate of 8.00 C/s 1) To find the value of the displacement current through a circular loop of radius, r=9 cm centered on the axis of the capacitor. 2) To find the value of the displacement current through a circular loop of radius, r=21 cm centered on the axis of the capacitor. 3) To find the magnitude of the magnetic field between the capacitor plates at a radius, r=9 cm from the axis of the capacitor.Solution: 1) Here, to find the value of the displacement current through a circular loop of radius r=9 cm. Here, by using the formula, id=dqdtπR2×πr2 R>>r Now, substitute the values in above equation, Where as, dqdt=9C/s , r=0.09 , R=0.16 id=(9 C/s)(0.16)2×(0.09)2 id=2.85 A2) Now, to find the value of the displacement current through a circular loop of radius, r=21 cm, By using the formula, id=dqdtπR2×πr2 Here, R=r Now, substitute the values in above equation, Where the values are, dqdt=9C/s , r=0.21 id=dqdtπR2×πr2 id=9 A3) Here, to find the magnitude of the magnetic field between the capacitor plates at a radius, r=9 cm, By using the formula, B=μ0id2πr Substitute the values in above equation, Where, μ0=4π×10-7H/m , id=2.85 A , r=0.09 B=(4π×10-7)(2.85)(2π)(0.09) B=(2×10-7)(2.85)(0.09) B=6.33 TFinal answer: The value of the displacement currents are, 1) id=2.85 A , 2) id=9 A And the magnitude of the magnetic field between the capacitor plates is, 3) B=6.33 T

Answered: Displacement Current A parallel plate…