2. In the 1-D problem shown below, a 5-MeV alpha particle is approaching a square potential barrier. a particle 10 MeV Calculate the transmission probability for the barrier widths of 1 fm and 5 fm, respectively.

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Greetings ,

I asked this on Bartleby

i got a somewhat straight answer . However I was told it was wrong then I asked what makes their answer wrong and not yours(to person who said Bartleby was wrong ) .

Please see photos 

thanks I'm also having problems with what k subscript 2 = squreroot of 2 m(mass) c^2. That's can't be speed of light it's not in the formula . 

 

2. In the 1-D problem shown below, a 5-Me V alpha particle is approaching a square
potential barrier.
a particle
10 MeV
Calculate the transmission probability for the barrier widths of 1 fm and 5 fm,
respectively.
11
of dim
Transcribed Image Text:2. In the 1-D problem shown below, a 5-Me V alpha particle is approaching a square potential barrier. a particle 10 MeV Calculate the transmission probability for the barrier widths of 1 fm and 5 fm, respectively. 11 of dim
(2)
T=
E (Vo- E)
whare fe, = Nz m(Vo-E)
Nzmc? (IOMev- š MeV)
N2(4) (931.5 Mev) (5 Mev)
197.329 Mev. fum
= 0,978 fm
(0.978) (1) fo.918) (1)
e
• For a=1 fm
-e
Sinh (hesa)
2
= l,259
て=
= 0.386
(lo Mev)2
(5 Mev) (10-5)MeV.
For a = 5 fum ,
(0.978) (5)
-(0.774) (5)
Siuh (fez a) =
* 66.47
%3D
2
= 0, 000226
I+ (66.47)²
Transcribed Image Text:(2) T= E (Vo- E) whare fe, = Nz m(Vo-E) Nzmc? (IOMev- š MeV) N2(4) (931.5 Mev) (5 Mev) 197.329 Mev. fum = 0,978 fm (0.978) (1) fo.918) (1) e • For a=1 fm -e Sinh (hesa) 2 = l,259 て= = 0.386 (lo Mev)2 (5 Mev) (10-5)MeV. For a = 5 fum , (0.978) (5) -(0.774) (5) Siuh (fez a) = * 66.47 %3D 2 = 0, 000226 I+ (66.47)²
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