2. A Disney Cruise-ship decides to test its new sea monster attack mechanism by an angle of 60 degrees. V=150m/s) angle 600 a. How far will it land? dist (R) u²pin ²60° S (150)2-sin (120°). 3.8m/ b. What is the maximum height it will achieve? 4= 9= 9.807/5 (constant) 1 = U²sin ²600 29 R 2.Usin60 3 - 41 = (150) 2²-23 in 60² 2(3.8) m/s or You Tal c. How long until it hits the water? t 1588.32 m -860.96 m t = 2.150m/s 3in 60 5.8 m/s² = 26.57 sec d. As the ship was attempting its second test shot with the same angle and velocity, a 4,000m tall sea monster suddenly emerged from the water 1600m away from the ship. What time will the cannonball strike the monster?
2. A Disney Cruise-ship decides to test its new sea monster attack mechanism by an angle of 60 degrees. V=150m/s) angle 600 a. How far will it land? dist (R) u²pin ²60° S (150)2-sin (120°). 3.8m/ b. What is the maximum height it will achieve? 4= 9= 9.807/5 (constant) 1 = U²sin ²600 29 R 2.Usin60 3 - 41 = (150) 2²-23 in 60² 2(3.8) m/s or You Tal c. How long until it hits the water? t 1588.32 m -860.96 m t = 2.150m/s 3in 60 5.8 m/s² = 26.57 sec d. As the ship was attempting its second test shot with the same angle and velocity, a 4,000m tall sea monster suddenly emerged from the water 1600m away from the ship. What time will the cannonball strike the monster?
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Hello! Could you please help me to solve the “D” question and review all my work for this questions
![### Projectile Motion: Cannonball Example
**2. Scenario:**
A Disney cruise ship tests its new sea monster attack mechanism by firing a cannonball at a velocity of 150 m/s at an angle of 60 degrees.
- Given:
- Initial velocity (\(U\)) = 150 m/s
- Angle = 60 degrees
- Gravity (\(g\)) = 9.8 m/s² (constant)
#### a. How far will it land? (R)
The range (\(R\)) is calculated using the formula:
\[
R = \frac{U^2 \sin(2 \cdot 60^\circ)}{g}
\]
\[
R = \frac{(150)^2 \cdot \sin(120^\circ)}{9.8}
\]
Result: \(R = 1588.32\, \text{m}\)
#### b. What is the maximum height it will achieve? (H)
The maximum height (\(H\)) is given by:
\[
H = \frac{U^2 \sin^2(60^\circ)}{2g}
\]
\[
H = \frac{(150)^2 \cdot \sin^2(60^\circ)}{2 \cdot 9.8}
\]
Result: \(H = 860.26\, \text{m}\)
#### c. How long until it hits the water? (t)
Time (\(t\)) is calculated with:
\[
t = \frac{2 \cdot U \cdot \sin(60^\circ)}{g}
\]
\[
t = \frac{2 \cdot 150 \cdot \sin(60^\circ)}{9.8}
\]
Result: \(t = 26.57\, \text{seconds}\)
#### d. Additional Problem
During a second test shot, a 4000m sea monster emerged 1600m away from the ship. Calculate when the cannonball strikes the monster.
(Note: Ensure calculations take into account the problem constraints and logic when applied to this extended scenario.)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fee23a48e-d4e2-4e13-b93f-00a50c9fa46d%2Ffca5007a-1ac1-40d1-8a8d-824d7d0bf0a9%2Foss904_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Projectile Motion: Cannonball Example
**2. Scenario:**
A Disney cruise ship tests its new sea monster attack mechanism by firing a cannonball at a velocity of 150 m/s at an angle of 60 degrees.
- Given:
- Initial velocity (\(U\)) = 150 m/s
- Angle = 60 degrees
- Gravity (\(g\)) = 9.8 m/s² (constant)
#### a. How far will it land? (R)
The range (\(R\)) is calculated using the formula:
\[
R = \frac{U^2 \sin(2 \cdot 60^\circ)}{g}
\]
\[
R = \frac{(150)^2 \cdot \sin(120^\circ)}{9.8}
\]
Result: \(R = 1588.32\, \text{m}\)
#### b. What is the maximum height it will achieve? (H)
The maximum height (\(H\)) is given by:
\[
H = \frac{U^2 \sin^2(60^\circ)}{2g}
\]
\[
H = \frac{(150)^2 \cdot \sin^2(60^\circ)}{2 \cdot 9.8}
\]
Result: \(H = 860.26\, \text{m}\)
#### c. How long until it hits the water? (t)
Time (\(t\)) is calculated with:
\[
t = \frac{2 \cdot U \cdot \sin(60^\circ)}{g}
\]
\[
t = \frac{2 \cdot 150 \cdot \sin(60^\circ)}{9.8}
\]
Result: \(t = 26.57\, \text{seconds}\)
#### d. Additional Problem
During a second test shot, a 4000m sea monster emerged 1600m away from the ship. Calculate when the cannonball strikes the monster.
(Note: Ensure calculations take into account the problem constraints and logic when applied to this extended scenario.)
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