Differentiate f(x) = ln (cos x). | f'(x) = tan x f'(x) = -tan x f'(x) = csc x sec x f'(x) = − csc x sec x

Q: tan(x) - 3 sec(x) If f(x) = - f'(x) = f'(-2) = then:

A: The given function is: fx=tanx-3secx   As we know that; The Quotient rule: fg'=f'·g-g'·fg2 And Use…

Q: Let f(x) = 2 csc (7x) f'(x) = - -14 cot (7x) csc (7x) X

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Q: Let f(x) 4 cos x + 2 tan x f' (æ) = r(금)- f'

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Q: If f(x) = cos a- 5 tanx, then %3D f'(x) = %3D f'(5) =

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Q: If f(x) = f'(x) = f'(4) = tan x - 5 sec x 3x² tan(x) sec(x) X

A: The Quotient Rule:Use the common derivatives:

Q: If f(x)= f'(x) = f'(4) = = 3 tan x X " then

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Q: Use logarithmic differentiation to find the derivative of the function. y = (tan x)8/x 8 -tan(x) tan…

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Q: f(x)=x+sinx / x2+cosx f '(x)=?

A: Given function: Now,

Q: F(x)=2x sin(x)Tan(x) find f'(x)

A: Use the concept of derivative of the form  f = uvw

Q: Calculate the derivative of: ƒ'(x) = → f(x) = - cos-¹(15x) sin ¹(15x)

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Q: Let f(x) = x² tan-'(8x) f'(x) =

A: Given: Now,

Q: If f(x) = 2 tan-'(8 sin(4x)), f'(x) =

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Q: If f(x) f'(x) = COS x 3 tan x, then - f' (5) =

A: Derivative of cosx is -sinx.

Q: Find the derivative of the given function. COS ³ (1) g(x) = 2 cos3 O a) g'(x) = -3 cos² (sin() Ob)…

A: Given, g(x)=2 cos3x2

Q: f (x) = csc(cos(e*+1))

A: We have to find the derivatives of given function: fx=coseccose5x+1 We know following derivatives…

Q: If f(x) = f'(x) = f'(1) = = tan a - sec x 4

A:

Q: If f(x) = f'(x) = = f'(4) = 3 tan x, then -sin(x) - 3 sec²(x) COS X >

A: we need to find out the derivative for the given function

Q: If f(x) = 3 sec(6x), find ƒ'(x). 18 sec (6x) tan (6x) Find f'(5).

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Q: = If f(x) = f'(x) = ƒ'(5) = 4 tan x, then - sin(x)-4 sec² (x) Cos x

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Q: Find the derivative of -4 f(x) = 6x° /x +

A: Given function :